3 years ago

Charles law increases keep pressure constant then you observe blank

Physics

1 answer:

OLga [1]3 years ago

7 0

If you decrease the pressure of a fixed amount of gas, its volume will increase.

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A small artery has a length of 1.10 × 10-3 m and a radius of 2.50 × 10-5 m. If the pressure drop across the artery is 1.15 kPa,

levacccp [35]

Answer:

$7.69533\times 10^{-11}\ m^3/s$

Explanation:

P = Pressure difference = 1.15 kPa

r = Radius = $2.5\times 10^{-5}\ m$

$\eta$ = Viscosity of liquid = $2.084\times 10^{-3}\ Pas$

l = Length of artery = $1.1\times 10^{-3}\ m$

From Poiseuille's equation we have

$Q=\frac{\pi Pr^4}{8\eta l}\\\Rightarrow Q=\frac{\pi 1.15\times 10^3\times (2.5\times 10^{-5})^4}{8\times 2.084\times 10^{-3}\times 1.1\times 10^{-3}}\\\Rightarrow Q=7.69533\times 10^{-11}\ m^3/s$

The flow rate of blood is $7.69533\times 10^{-11}\ m^3/s$

8 0

2 years ago

A gas takes up a volume of 17.0 L, has a pressure of 2.30 atm, and a temperature of 299 K. If the temperature is raised to 350.0

Maurinko [17]

Answer:

new volume = 30.513L

Explanation:

V1 =17L , P1= 2.3atm , T1=299K , T2=350K , P2 =1.5atm, V2=?

To find the new volume of the gas we will use the combined gas law.

The combined gas law combines Boyle's law, Charles law and Gay-Lussac's law. Its states that the ratio of the product of pressure and volume to temperature is equal to a constant. its expressed mathematically below.

$\frac{V1P1}{T1} = \frac{V2P2}{T2}$