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Thepotemich [5.8K]
4 years ago
13

A fluid particle flowing along a stagnation streamline, as shown in Video V4.9 and Fig. P4.35, slows down as it approaches the s

tagnation point. Measurements of the dye flow in the video indicate that the location of a particle starting on the stagnation streamline a distance s = 0.8 ft upstream of the stagnation point at t = 0 is given approximately by s = 0.8e-0.61t where t is in seconds and s is in feet.(a) Factor the relation for the speed as a function of position out of the relation for speed as a function of time. What is the expression for speed V in terms of position s only?(b) For the position as a function of time given in the problem, what is the relation between the speed of the particle V and time t?(c) Symbolically, what does the derivative of position with respect to time equal?

Engineering
2 answers:
kupik [55]4 years ago
5 0

Answer:

See explanations for step by step procedures into getting answer.

Explanation:

Given that:

A fluid particle flowing along a stagnation streamline, as shown in Video V4.9 and Fig. P4.35, slows down as it approaches the stagnation point. Measurements of the dye flow in the video indicate that the location of a particle starting on the stagnation streamline a distance s = 0.8 ft upstream of the stagnation point at t = 0 is given approximately by s = 0.8e-0.61t where t is in seconds and s is in feet.(a) Factor the relation for the speed as a function of position out of the relation for speed as a function of time. What is the expression for speed V in terms of position s only

(b) For the position as a function of time given in the problem, what is the relation between the speed of the particle V and time t

(c) Symbolically, what does the derivative of position with respect to time equal.

See comolete solving at attachment

amm18124 years ago
5 0

Answer:

Explanation:

Step by step explanation is given in the attached document.

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A

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Explain how you could transmit two independent base-band information signals by using SSB on a common carrier frequency.
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Using Hilbert Transformation, we can transmit two independent base-band information signals by using SSB on a common-carrier frequency.

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4 years ago
The pressure distribution over a section of a two-dimensional wing at 4 degrees of incidence may be approximated as follows: Upp
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Answer:

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Cp_l=-0.4 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.4*0.6+0.4*0.1

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\Delta Cp=Cp_l-Cp_u\\\Delta Cp=-0.4*0.6+0.4*0.1-(-0.8*0.6-0.4*0.1)\\\Delta Cp=-0.4*0.6+0.4*0.1+0.8*0.6+0.4*0.1\\\Delta Cp=0.4*0.6+0.4*0.2\\\Delta Cp=0.32

Now the Lift Coefficient is given as

C_L=\Delta C_p cos(\alpha_i)\\C_L=0.32\times cos(4*\frac{\pi}{180})\\C_L=0.3192

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C_M=-0.3*0.4*0.6-(0.6+\dfrac{0.4}{3})*0.2*0.4\\C_M=-0.1306

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