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4 years ago

Explain how you could transmit two independent base-band information signals by using SSB on a common carrier frequency.

Engineering

1 answer:

Goshia [24]4 years ago

4 0

Answer:

Using Hilbert Transformation, we can transmit two independent base-band information signals by using SSB on a common-carrier frequency.

Explanation:

In SSB modulators, we pre-process a real signal by Hilbert Transform filter to form another real signal
The signal has the same spectral amplitude but has 90° phase shift at each frequency relative to its input signal.
The ordered pair gets almost all of its negative components cancelled
thus, with the use of Hilbert Transformation, we can transmit two independent base-band information signals by using SSB on a common carrier frequency.

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Convert

Helen [10]

Answer:

(a) $1.308\times 10^{-4}m/sec$

(b)57.33831 pound/cubic feet

Explanation:

We have

(a) 760 miles / hour

We know that $1\ mile\ =0.00062m$

And 1 hour = 60×60=3600 sec

So $760miles/hour=\frac{760\times 0.00062meter}{3600sec}=1.308\times 10^{-4}m/sec$

(b) 927 kg/cubic meter to mass/cubic foot

We know that 1 kg = 2.20 pound

So 921 kg = 921×2.20=2026.2 pound

We know that 1 cubic meter = 35.31 cubic feet

So 57.33831 pound / cubic feet

$5.37\times 10^3kj/min=\frac{5.37\times 1000kj}{60sec}=89.5kj/sec$

We know that 1 kj /sec = 1.341 hp

So 89.5 kj/sec = 89.5××1.341=120.1095 hp

7 0

4 years ago

Assume there exists some hypothetical metal that exhibits ferromagnetic behavior and that has (1) a simple cubic crystal structu

scoray [572]

Answer:

a. 2.9218x10^(-29) m^3

b. 7.1230x10^(28) atoms/m^3

c. 2.0812 BM/atom

Explanation:

Atomic radius r = 0.154 nm

saturation flux density Bs = 0.83 tesla

- the formula for the volume of the simple cubic crystal (Vc) = a^3 = (2r)^3

= (2 x 0.154x10^-9)^3

= 2.9218x10^-29 m^3

- The formula for the Bohr magneton per atom with respect to VC, Bs, permeability of the vacuum Uo and magnetic moment per Bohr magneton Ub is;

Bohr magneton per atom nb = (Bs x VC) / (Ub x Uo)

= (0.83 x 2.9218x10^-29) / (9.27x10^-24) x(1.257x10^-6)

= 2.4251x10^-29 / 1.1652x10^-29

= 2.0812 BM/atom

- Number of atoms per Vc, N = nb / Vc

= 2.0812 / 2.9218x10^-29 = 7.1230x10^28 atoms

3 0

3 years ago

Define cooling tower "range" as it applies to cooling towers.

Arlecino [84]

Answer:

The answer to the range of a cooling tower is the difference between the temperature of the water going in and the temperature of the water going out of the tower.

Explanation:

Cooling towers are used to cool a stream of water using the air of the environment where it's placed or installed. In theory, the lowest temperature the water can be cooled to would be the wet bulb temperature (temperature of the air going in the cooling tower). The range would be the difference (R=Ti-To) between the temperature of the hot water going in and the cooler water going out.

8 0

3 years ago

The density of a liquid is to be determined by an old 1-cm-diameter cylindrical hydrometer whose division marks are completely w

Simora [160]

Answer:

1064.8 kg/m³

Explanation:

Weight of the hydrometer = ρghA where ρ is the density, g is acceleration due to gravity, h is the submerged height and A is the cross sectional area.

W in water = ρwghwA

W in liquid = (ρliq)g hliq A where the cross sectional area is constant

W in water = W in liquid

(ρw)ghwA = (ρliq)g hliq A where ρw is density of water, ρliq is the density of liquid and hw and hliq are the heights of the liquid and that water. g acceleration due to gravity cancel on both sides as well as the constant A

pliq = $\frac{hw}{hliq}$ × 1000 kg /m³ ( density of water) =( $\frac{23}{23-1.4}$ ) × 1000 = 1064.8 kg/m³

8 0

3 years ago

What do you enjoy most and least about engineering?

melisa1 [442]

Answer:

“I really love the design work in engineering, the face-to-face interaction with clients, and the opportunity to see projects come to life. But if I had to pick one thing that I don’t enjoy as much, I would have to say it’s contract preparation.”

5 0

3 years ago

Read 2 more answers