Answer:
The answer 1 is correct.
Explanation:
When a junction called the p-n is forward biased, the capacitance of diffusion will form or structured across depletion layers.
When at a higher frequency or frequencies, the dopants, are vibrated across the metallurgical junction and the doping profiles smooths out.
Moisture content is measured in terms of pounds of water per pound of air (lb water/lb air) or grains of water per pound of air (gr. of water/lb air).
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Pseudocodes are used as a prototype of an actual program.
The error in the pseudocode is that, the while loop in the pseudocode will run endlessly.
From the pseudocode, the first line is:
<em>Declare Boolean finished = false</em>
The while loop is created to keep running as long as <em>finished = false.</em>
So, for the while loop to end, the finished variable must be updated to true.
This action is not implemented in the pseudocode.
Hence, the error in the pseudocode is that, the while loop is an endless loop
Read more about pseudocodes at:
brainly.com/question/17442954
Answer:
The inventor's claim is false in the sense that no thermal machine can violate the first thermodynamic law.
Explanation:
The inventor's claim could not be possible as no thermal machine can transfer more heat than the input work consumed. If we expose the thermal efficiency:
Where Q and W both must be in the same power unit, so we will convert the remove heat from BTU/hr to hp:
Therefore by comparing, we notice that the removing heat of 4.75 hp is large than the delivered work of 1.11 hp. By evaluating the efficiency:
[tex]n=4.75 hp / 1.1 hp = 4.3 > 1[/tex]
Answer:

Explanation:
We are given:
m = 1.06Kg

T = 22kj
Therefore we need to find coefficient performance or the cycle


= 5
For the amount of heat absorbed:

= 5 × 22 = 110KJ
For the amount of heat rejected:

= 110 + 22 = 132KJ
[tex[ q_H = \frac{Q_L}{m} [/tex];
= 
= 124.5KJ
Using refrigerant table at hfg = 124.5KJ/Kg we have 69.5°c
Convert 69.5°c to K we have 342.5K
To find the minimum temperature:
;

= 285.4K
Convert to °C we have 12.4°C
From the refrigerant R -134a table at
= 12.4°c we have 442KPa