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ziro4ka [17]
3 years ago
6

Which information about the earth would not be represented when a globe is used as a model?

Physics
1 answer:
egoroff_w [7]3 years ago
5 0
A globe sitting on the desk can't demonstrate the speed of axial rotation
or the speed of orbital revolution.
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Unpolarized light whose intensity is 1.46 W/m2 is incident on the polarizer in the drawing. (a) What is the intensity of the lig
Serhud [2]

Answer:

0.73 W/m²

0.2522 W/m²

Explanation:

I_0 = Unpolarized light = 1.46 W/m²

\theta = Analyzer angle = 54°

Light through first filter

I_1=\frac{I_0}{2}\\\Rightarrow I_1=\frac{1.46}{2}\\\Rightarrow I_1=0.73\ W/m^2

The intensity of the light leaving the polarizer is 0.73 W/m²

After passing through analyzer

I=I_1cos^2\theta\\\Rightarrow I=0.73\times cos^2(54)\\\Rightarrow I=0.2522\ W/m^2

The intensity of the light that reaches the photocell is 0.2522 W/m²

6 0
3 years ago
A truck on a straight road starts from rest and accelerates at 1.4 m/s 2 until it reaches a speed of 22 m/s. Then the truck trav
Zolol [24]

Answer:

42.11 sec

Explanation:

In first part : The truck start from the rest that is u = 0 m/sec

Acceleration is given as a=1.4m/sec^2

It reaches to a velocity of 22 m/sec so v=22 m/sec

Now according to first law of motion v=u+at

22=0+1.4\times t

t=15.71sec

In second part : The truck maintain a constant speed for 22 sec

In third  part : The truck takes an additional 4.4 sec for stopping

So total time in which the truck is in motion =15.71+22+4.4=42.11 sec

3 0
4 years ago
Bone has a Young’s modulus of about
Softa [21]

Answer:

4.25 mm

Explanation:

σ = E ∙ ∆L/L₀

where σ is stress,

E is Young's modulus,

and ∆L/L₀ is strain (∆L is the deflection, L₀ is the initial length).

Plugging in values:

1.53×10⁸ Pa = (1.8×10¹⁰ Pa) ∆L / (500 mm)

∆L = 4.25 mm

5 0
4 years ago
I need some help as soon as possible
EastWind [94]

8) speed

9)velocity

10)velocity

11)velocity

3 0
4 years ago
the initial velocityof a particle along x axis is u at t=0 x=0 and its acceleration is given by a =2x then whats the correct equ
miskamm [114]

Answer:

v² = u² + 2x²

Explanation:

v² = u² + 2as​ is only valid for constant acceleration.  Here, the acceleration is a function of position.  We can find the function of velocity by integrating.  Acceleration is the derivative of velocity with respect to time:

a = 2x

dv/dt = 2x

Apply chain rule:

dv/dt = dx/dt × dv/dx

dv/dt = v × dv/dx

Therefore:

v dv/dx = 2x

Separate the variables and integrate:

v dv = 2x dx

½ v² |ᵤᵛ = x² |₀ˣ

½ (v² − u²) = x²

v² − u² = 2x²

v² = u² + 2x²

8 0
3 years ago
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