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antoniya [11.8K]
3 years ago
7

A force transmitted through a string or rope is called what

Physics
2 answers:
Lunna [17]3 years ago
8 0

Answer:

The tension force is the force that is transmitted through a string, rope, cable or wire when it is pulled tight by forces acting from opposite ends.

Sergeu [11.5K]3 years ago
4 0

Answer:

Tension force

Explanation:

Have a good day :)

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A physics professor demonstrates the Doppler effect by tying a 600 Hz sound generator to a 1.0-m-long rope and whirling it aroun
nalin [4]

Answer:

Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz

Explanation:

Given data

Source Frequency fs=600Hz

Length r=1.0m

RPM=100 rpm

The speed of the generator is calculated as:

v_{s}=rw\\v_{s}=r(2\pi f)

Substitute the given values

v_{s}=(1.0m)2\pi (\frac{100}{60}rev/s )\\v_{s}=10.47m/s

For approaching generator the frequency is calculated as:

f_{+}=\frac{f_{s}}{1-\frac{v_{s}}{v} }\\f_{+}=\frac{600Hz}{1-\frac{10.47m/s}{343m/s} } \\f_{+}=620Hz

On the other hand,for the receding generator,Doppler's effect is expressed as:

 f_{-}=\frac{f_{s}}{1+\frac{v_{s}}{v} }\\f_{-}=\frac{600Hz}{1+\frac{10.47m/s}{343m/s} } \\f_{-}=580Hz

Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz

8 0
4 years ago
Make the following conversion. 120 mL = _____ cm³ 12.0 1200 120 1.20
omeli [17]
120 is your answer. 120 mL = 120 cm^3
7 0
3 years ago
Read 2 more answers
How would i solve for force when there are multiple accelerations?
damaskus [11]

"Multiple accelerations" is a puzzling phrase, and I'd be curious to understand it
better.  Sadly however, you haven't explained it at all.

If the multiple accelerations are the accelerations of multiple objects, then
the net force on each object is the product of (its mass) x (its acceleration).

If the multiple accelerations are the acceleration of one object at different times,
then at any instant of time, the net force on the object is the product of (its mass) x
(its acceleration at that instant).

8 0
3 years ago
An object is initially moving at an unknown velocity. It accelerates at a rate of 2.0 m/s2 to a new velocity of 45 m/s in 10s. W
katrin2010 [14]

Answer:

Initial velocity=25m/s

Explanation:

acceleration(a)=2m/s^2

Final velocity(v)=45m/s

Time(t)=10seconds

Initial velocity(u)=?

V=u+axt

45=u+2x10

45=u+20

u=45-20

u=25m/s

6 0
4 years ago
A tire 0.500 m in radius rotates at a constant rate of 200 rev/min. Find the speed and acceleration of a small stone lodged in t
arsen [322]

Answer:

v = 10.47 m/s

a = 219.32 m/s²

Explanation:

The velocity of the stone can be given by the following formula:

v = r ω

where,

v = linear velocity of the stone = ?

r = radius of tire = 0.5 m

ω = angular velocity = (200 rev/min)(2π rad/1 rev)(1 min/60 s) = 20.94 rad/s

Therefore,

v = (0.5 m)(20.94 rad/s)

<u>v = 10.47 m/s</u>

<u></u>

The acceleration of the stone will be equal to the centripetal acceleration. Therefore,

a = v²/r

a = (10.47 m/s)²/0.5 m

<u>a = 219.32 m/s²</u>

8 0
3 years ago
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