Which graph shows a negative acceleration

Physics

1 answer:

SVETLANKA909090 [29]3 years ago

4 0

Answer:

The velocity-time graph shows a line with a negative (downward) slope (negative acceleration); the line is located in the positive region of the graph (positive velocity).

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hope that helps : )

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A material kept at high temperature is seen to emit photons with energies of 0.3 eV, 0.5 eV, 0.8 eV, 2.0 eV, 2.5 eV, and 2.8 eV.

sukhopar [10]

Answer:

0.3 eV, 0.5eV,, 8 eV, 2.0eV, 2.50 eV, 2.8 eV

Explanation:

In a given material the emission and absorption spectra are equivalent, for which the emission spectrum observed at high temperature for the material corresponds to the transition between the energy states of the material, the process is that the electrons exist from the ground state until an excited state and after a short period of time or these electrons relax emitting photons.

In the absorption process, the material is at low temperature, ideally at A = 0K, whereby all states are in the ground state and all excited states are empty. therefore it can absorb the beam energy for each transition given from the ground state to each excited edtado.

Consequently, the lines above the absorption oscillate lines coincide with the lines of emotion, this we see lines oscillate at 0.3 eV, 0.5eV,, 8 eV, 2.0eV, 2.50 eV, 2.8 eV

5 0

3 years ago

Your GPS shows that your friend’s house is 10.0 km away. But there is a big hill between your houses and you don’t want to bike

kati45 [8]

Answer:

The value is $c = 8 \ km$

Explanation:

From the question we are told that

The distance of friends house from your point is $a = 10 \ km$

The distance of your friends street from your street is $b = 6 \ km \ in the \ direction \ towards \ the \ north$

The diagram illustrating this question is shown on the first uploaded image

From the diagram we can apply by Pythagoras theorem as follows

$a^2 = b^2 + c^2$

=> $c = \sqrt{^2 - b^2}$

=> $c = \sqrt{ 10^2 - 6^2}$

=> $c = 8 \ km$

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3 years ago

A book falls off a shelf that is 10.0 m tall. What is the velocity at which the book hits the ground?

Elena L [17]

Answer:

14 m/s

Explanation:

The motion of the book is a free fall motion, so it is an uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. Therefore we can find the final velocity by using the equation:

$v^2 = u^2 + 2gd$