Actually Welcome to the Concept of the Rays of light.
Since we know that, The light ray on a shiny surface makes a angle with the normal, hence The Angle of incidence is equal to angle of reflection made with Normal Axis in the middle.
Thus Option c.) is correct.
C.) is the Answer.
Answer:
<em>The shortest distance to an object that this radar can detect would be </em>
<em>111 m</em>
Explanation:
The shortest distance is the minimum distance that would be detected by the radar, The time of oscillation can be obtained thus;
T = 1/f ..........1
but f= v/λ substituting f into equation 1 we have;
T = λ/v...............2
Where λ is the wavelength = 2.2 m
v is the velocity of light since the radar is an electromagnetic wave
= 3 x m/s
T = 2.2 m / 3 x m/s
T = 7.33 x s
<u>Calculating the time interval required by the pulse</u>
Since the interval of the pulse (t) is 100 times greater than the period of oscillation, the time of the pulse is expressed as;
t = 100 x T
t = 100 x 7.33 x s
t = 7.33 x s
Therefor the time of the pulse is 7.33 x s
<u>Calculating for the shortest distance of the radar</u>
The shortest distance of the radar can be obtained using the equation below;
λ_s = (t/2) x v ............3
Substituting into equation 3 we have
λ_s = (7.33 x /2) x 3 x
m/s
λ_s = 111 m
Therefore the shortest distance to an object that this radar can detect would be 111 m