Answer:
0.66 m/s
Explanation:
This is an inelastic collision, for that reason the conservation of momentum law allows us to determine the final velocity of both, the bullet and block together after the collision:
Answer:
433903.8 N
Explanation:
From work energy theorem, the total work done is equivalent to change in kinetic energy. Kinetic energy is depedant on speed and since pile drive finally comes to rest, then final velocity is zero. Also, its initial velocity is not given. Therefore, the sum of work due to gravity and beam equals to zero. Work due to gravity is product of mass of pile driver, acceleration due to gravity and height while work due to beam is a product of force and distance. Substituting the given values then
2300*9.81*3+(F*0.156)=0
F=-433903.84615384615384615384615384615384615 N
Approximately, the magnitude of force is 433903.8 N and it acts upwards
Answer:
15.8 m/s
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 32 m/s.
Acceleration (a) = – 1.5 m/s²
Time (t) = 10.8 s.
Final velocity (v) =?
Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:
Acceleration (a) = [final velocity (v) – initial velocity (u)] / time (t)
a = (v – u) /t
With the above formula, we can obtain the final velocity of go-cart driver as follow:
Initial velocity (u) = 32 m/s.
Acceleration (a) = – 1.5 m/s²
Time (t) = 10.8 s.
Final velocity (v) =?
a = (v – u) /t
– 1.5 = (v – 32) / 10.8
Cross multiply
(v – 32) = –1.5 × 10.8
v – 32 = – 16.2
Collect like terms
v = – 16.2 + 32
v = 15.8 m/s
Therefore, the final velocity of go-cart driver is 15.8 m/s.
We don't know what you mean by "lunar cycle".
It appears at the same place in your sky every 24 hours and 50 minutes on the average.
It revolved around the Earth every 27.32 days.
It displays a full set of "phases" every 29.53 days.
