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2 years ago

PLEASE HELP !! A 10 ohm resistor is connected to a 9V battery how much current is flowing through the circuit?

Physics

1 answer:

kompoz [17]2 years ago

8 0

Resitance (R)= 10 Ohm

Potential difference (V) = 9V

V= IR

I= V/R

I= 9/10

I= 0.9 Ampere

Therefore 0.9 Ampere of current is flowing through the circuit.

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Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 25.0 m above water wit

Rasek [7]

Complete question is;

Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 25.0 m above water with an initial speed of 20.0 m/s strikes the water with a final speed of 31.1 m/s, independent of the direction thrown

Answer:

It is proved that the final speed is truly 31.1 m/s

Explanation:

From energy - conservation principle;

E_i = Initial potential energy + Initial Kinetic Energy

E_i = U_i + K_i

Similarly, for final energy

E_f = U_f + K_f

So, expressing the formulas for potential and kinetic energies, we now have;

E_i = (m × g × y_i) + (½ × m × v_i²)

Similarly,

E_f = (m × g × y_f) + (½ × m × v_f²)

We are given;

y_i = 25 m

y_f = 0 m

v_i = 20 m/s

v_f = 31.1 m/s

So, plugging in relevant values;

E_i = m((9.8 × 25) + (½ × 20²))

E_i = 485m

Similarly;

E_f = m((9.8 × 0) + (½ × v_f²)

E_f ≈ ½m•v_f²

From energy conservation principle, E_i = E_f.

Thus;

485m = ½m•v_f²

m will cancel out to give;

½v_f² = 485

v_f² = 485 × 2

v_f² = 970

v_f = √970

v_f ≈ 31.1 m/s

7 0

2 years ago

a portable DVD player requires six 1.5-volt batteries to operate.if the resistance in the circuitis 7.2 ohms. what's the current

kupik [55]

Hello!

A portable DVD player requires six 1.5-volt batteries to operate. If the resistance in the circuit is 7.2 ohms, what is the current?

Data:

We have six 1.5 volt batteries, soon, your tension (V)

V = 1.5 * 6 = 9 Volts

R (resistance) = 7.2 ohms

I (Current intensity) = ? (in Amps)

Solving (Ohm's First Law):

$I = \dfrac{V}{R}$

$I = \dfrac{9}{7.2}$

$\boxed{\boxed{I= 1.25\:A}}\:\:\:\:\:\:\bf\blue{\checkmark}$

Answer:

The current is 1.25 amps

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