A 5 kg block is pushed across a table by a horizontal force of 40 N with an acceleration of 5 m/s^2. What is the frictional forc
1 answer:
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Answer:
u= 20.09 m/s
Explanation:
Given that
m = 0.02 kg
M= 2 kg
h= 0.2 m
Lets take initial speed of bullet = u m/s
The final speed of the system will be zero.
From energy conservation
1/2 m u²+ 0 = 0+ (m+M) g h
m u²=2 (m+M) g h
By putting the values
0.02 x u² = 2 (0.02+2) x 10 x 0.2 ( take g=10 m/s²)
u= 20.09 m/s
Answer:
The gauge pressure is
Explanation:
From the question we are told that
The height of the water contained is
The height of liquid in the cylinder is
At the bottom of the cylinder the gauge pressure is mathematically represented as
Where is the pressure of water which is mathematically represented as
Now is the density of water with a constant values of
substituting values
While is the pressure of oil which is mathematically represented as
Where is the density of oil with a constant value
substituting values
Therefore