log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
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I think the equation should be
where 3 is the common ratio of the exponential function
so the answer is C.
Answer:
-13ºC
Step-by-step explanation:
The temperature has fallen, so you subtract.
Answer:
2/3
Step-by-step explanation:
Your −3x + 3 −1 is not an equation and thus has no solution.
If, on the other hand, you meant
−3x + 3 = 1
then -3x = -2, and x = 2/3
Answer:
Step-by-step explanation:
Next time, please be sure to share the possible answer choices. Also, please use " ^ " to indicate exponentiation: x^2 + (2/3)x.
Let's actually "complete the square" here:
Starting with x^2 + (2/3)x, identify the coefficient of the x term (it is 2/3).
Take half of that, which results in 2/6, or 1/3.
Square this result, obtaining (1/3)^2 = 1/9.
Add to, and then subtract from, this square:
x^2 + (2/3)x + 1/9 - 1/9
Rewrite x^2 + (2/3)x + 1/9 as the square of a binomial:
(x + 1/3)^2 - 1/9
In review: add 1/9 to, and then subtract 1/9 from, x^2 + (2/3)x
