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guajiro [1.7K]
3 years ago
14

HELP PLS! WILL MARK BRAINLIEST! Read each problem statement and decide if

Mathematics
1 answer:
pogonyaev3 years ago
4 0

Answer:

The answer is in the web link

Step-by-step explanation:

1.) https://shsmrward.weebly.com/uploads/1/0/0/3/10037735/independentdependent_ak.pdf

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A mallard duck is 56 to 65 cm long if the duck travel 97.8 miles at top speed in 1.5 hours how far did it travel in 1 hour
ra1l [238]

Answer:

They traveled 2.71 in 1 hr

Step-by-step explanation:

97.8 divided by 1.5 then multiply that by 1hr

6 0
2 years ago
When a certain number is divided by 4, the answer is 160 with a remainder of 2. What is the number?
Veseljchak [2.6K]
X/4=160R2      X=642. I hope I helped you out.        160x4=640+2=642.
4 0
3 years ago
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The perimeter of a square is 18 2.<br> Determine the length of the diagonal.
Natalija [7]
The diagonal of the square is 9.1?
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3 years ago
Convert decimal to a fraction in simplest form 0.20<br><br> HELP HELP!!!!
Vitek1552 [10]

Answer: 2/10

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Let II be the tangent plane to the graph of f(x, y) = 8 – 2x^2 – 3y^2 at the point (1, 2,-6). Let S, x² + y^2 + z = 4 be another
stealth61 [152]

Let F(x,y,z)=f(x,y)-z. The tangent plane to f(x,y) at (1, 2, -6) has equation

\nabla F(1,2,-6)\cdot(x-1,y-2,z+6)=0

We have

\nabla F(x,y,z)=(-4x,-6y,-1)\implies\nabla F(1,2,-6)=(-4,-12,-1)

Then the tangent plane has equation

(-4,-12,-1)\cdot(x-1,y-2,z+6)=0\implies -4(x-1)-12(y-2)-(z+6)=0\implies 4x+12y+z=22

Let g(x,y)=4-x^2-y^2, and G(x,y,z)=g(x,y)-z. The tangent plane to S at a point (a,b,c) is

\nabla G(a,b,c)\cdot(x-a,y-b,z-c)=0

We have

\nabla G(x,y,z)=(-2x,-2y,-1)\implies \nabla G(a,b,c)=(-2a,-2b,-1)

so that this plane has equation

(-2a,-2b,-1)\cdot(x-a,y-b,z-c)=0\implies2ax+2by+z=2a^2+2b^2+c

In order for this plane to be parallel to the previous plane, we need to have

\begin{cases}2a=4\\2b=12\end{cases}\implies a=2,b=6\implies g(a,b)=c=-36

so the point we're looking for is (2, 6, -36).

6 0
3 years ago
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