Dryness and temperature are the primary reasons but also the type of honey.
Answer:

Explanation:
Hello,
In this case, since the undergoing chemical reaction is:

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

Regards.
Answer:
4.4g
Explanation:
Mass of CaCO3 = 10g
Mass of CaO = 5.6g
Mass of CO2 =?
Mass of CaCO3 = Mass of CaO + Mass of CO2
Mass of CO2 = Mass of CaCO3 — Mass of CaO
Mass of CO2 = 10 — 5.6
Mass of CO2 = 4.4g
Answer:
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Answer:
water helps u a lot
Explanation:
water vaper is gas that rises up into the air