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2 years ago

The ___ of a bottle tells you how much liquid it can hold. what is the anewer

Chemistry

2 answers:

muminat2 years ago

7 0

Capacity is a bottle which tells you how much liquid it can hold

Sonbull [250]2 years ago

5 0

Answer:

Volume

Explanation:

Volume is how much of a substance something can hold!

Hope this helped, have a nice day! :)

You might be interested in

How much faster does sound travel in the ocean then in the rainforest

Natali [406]

Answer:

Sound travels over 4 times faster in the ocean than it does on land.

Explanation:

Speed of sound in water is approximately 1500 meters per second

and the speed of sound in air is approximately 340 meters per second.

Kono Dio Da!!!

7 0

3 years ago

A gas mixture of Ne and Ar has a total pressure of 4.00 atm and contains 16.0 mol of gas. If the partial pressure of Ne is 2.75

Stolb23 [73]

Answer:

5 moles of Argon is present in the mixture.

Explanation:

Total pressure of the gaseous mixture = 4 atm

Total number of moles = 16

Partial pressure of Ne = 2.75 atm

By Dalton's law of partial pressure, the total pressure of gaseous mixture is the sum of partial pressures of individual gases which are non-reactive.

Hence:

$P_{total}=P_{Ar}+P_{Ne}\\4=P_{Ar}+2.75\\P_{Ar}=1.25\ atm$

Also :

Partial pressure = mole fraction*total pressure

$P_{Ar}=X_{Ar}P_{total}$

$X_{Ar}=\frac{1.25}{4}=0.3125$

$\frac{n_{Ar}}{n_{total}}=0.3125\\n_{Ar}=5$

∴Number of moles of Argon = 5

4 0

3 years ago

If the rate law for the reaction A LaTeX: \longrightarrow

Nostrana [21]

k=.240/(.4)^2=1.5 assuming [A]2 means [A] squared

6 0

3 years ago

Consider the reaction 4PH3(g) → P4(g) + 6H2(g) At a particular point during the reaction, molecular hydrogen is being formed at

Svetllana [295]

Answer:

The rate at which $P_4$ is being produced is 0.0228 M/s.

The rate at which $PH_3$ is being consumed is 0.0912 M/s.

Explanation:

$4PH_3\rightarrow P_4(g)+6H_2(g)$

Rate of the reaction : R

$R=\frac{-1}{4}\frac{d[PH_3]}{dt}=\frac{1}{6}\frac{d[H_2]}{dt}=\frac{1}{1}\frac{d[P_4]}{dt}$

The rate at which hydrogen is being formed = $\frac{d[H_2]}{dt}=0.137 M/s$

$R=\frac{1}{6}\frac{d[H_2]}{dt}$

$R=\frac{1}{6}\times 0.137 M/s=0.0228 M/s$

The rate at which $P_4$ is being produced:

$R=\frac{1}{1}\frac{d[P_4]}{dt}$

$0.0228 M/s=\frac{1}{1}\frac{d[P_4]}{dt}$

The rate at which $PH_3$ is being consumed :

$R=\frac{-1}{4}\frac{d[PH_3]}{dt}$

$0.0228 M/s\times 4=\frac{-1}{1}\frac{d[PH_3]}{dt}$

$\frac{-1}{1}\frac{d[PH_3]}{dt}=0.912 M/s$

6 0

3 years ago

a solution containing 80 g of KCL in 200 g of H2O at 50 degrees celcius is cooled to 20 degrees celcius. How many grams of KCL r

Varvara68 [4.7K]

Answer:

12g KCl will be crystallized

Explanation:

To solve this problem you need to know solubility of KCl in water at 20°C is 34g per 100g of water.

That means the maximum concentration of KCl you can dissolve at 20°C in 200g of water is 34g×2 = 68g of KCl

As solution containing 80g of KCl, the extra KCl will be crystallized after cooling, that is:

80g of KCl - 68g of KCl = <em>12g KCl will be crystallized</em>

I hope it helps!

8 0

3 years ago