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irakobra [83]
3 years ago
15

Indentify two advantages in daylight saving time

Chemistry
2 answers:
ANEK [815]3 years ago
7 0
Hello Melindayosiff ! 

Two advantages in daylight saving time are...

- It saves electricity use (it decreases use of electricity)
- It provides and extra hour of daylight at night

I hope I was able to help you out ! :D 
Savatey [412]3 years ago
5 0
More sleep and longer days or nights
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How much energy is transferred from a plant to an herbivore that eats it? A. 5% B. 10% C. 20% D. 90%
Tema [17]

Answer:

B. 10%

Explanation:

6 0
3 years ago
If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
irinina [24]

Answer:

4.13 g

Explanation:

Data Given:

Amount of CO₂ Produced = 15 g

Amount of Oxygen = 11 g

Amount of Carbon used = ?

Solution:

Suppose Carbon dioxide (CO₂) is formed by the reaction of carbon and oxygen then the reaction will be as below

                            C   +   O₂    -------------> CO₂

                          1 mol    1 mol                  1 mol

we come to know from the above reaction that

1 mole of carbon react with 1 mole of oxygen to produce 1 mol of carbon dioxide.

molar mass of C = 12 g/mol

molar mass of O₂ = 32 g/mol

molar mass of CO₂ = 12 + 2(16) = 44 g/mol

if we represent mole in grams then

           C               +                        O₂                     ------------->        CO                 1 mol (12 g/mol)                      1 mol (32 g/mol)                      1 mol (44 g/mol)

                   

              C   +   O₂    -------------> CO₂

            12 g       32 g                   44 g

So,

we come to know that 32 g of Oxygen combine with 12 g  of oxygen produce 44 g CO₂

So now how much of Carbon will be combine with 11 g of oxygen

apply unity formula

                32 g of  O₂ ≅ 12 g of  C

                  11 g of O₂  ≅  g of  C

by doing cross multiplication

           g of C = 12 g x 11 g / 32 g

           g of C = 132 g / 32 g

           g of C = 4.13 g

So,

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

to check this answer

we use the above information

                     12 g of  C ≅ 44 g of CO₂

                     4.13 g of C ≅  g of  CO₂

by doing cross multiplication

                    g of  CO₂ = 44 g x 4.13 g / 12 g

                    g of CO₂ = 15g

So it is confirmed that

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

4 0
2 years ago
When a chemical recstion has oxygen what does it clasify as
Murrr4er [49]

Answer: Combustion.

Explanation:

7 0
3 years ago
How much heat is absorbed by 15.5g of water when it's temperature is increased from 20.0C the specific heat of the water is 4.18
Anuta_ua [19.1K]
Hello!

The exercise doesn't say the final temperature, but we are going to assume that the increase is of 20 °C (The procedure is the same, just change the final temperature) To calculate the heat absorbed by water, we need to use the equation for Heat Transfer, in the following way (assuming that the heat increase is 20°C):

Q=m*C* \Delta T=15,5 g * 4,184 (J/g^\circ C) * 20 ^\circ C=1297,04 J

So, the Heat absorbed by water is 1297,04 J

Have a nice day!
7 0
2 years ago
How many grams of lithium nitrate, LiNO3 (68.9 g/mol), are required to prepare 342.6 mL of a 0.783 M LiNO3 solution ? A) 0.00389
Anika [276]

Answer:

b) 18.5 g

Explanation:

The first step is the <u>calculation of number of moles</u> of LiNO_3 with the molarity equation, so:

M=\frac{#~mol}{L}

With the <u>volume in "L" units</u> (342.6 mL= 0.342 L ) we can <u>find the moles</u>, so:

0.783~M\frac{#~mol}{0.342~L}

#~mol=~0.783*0.342=0.268~mol~LiNO_3

Now, we have to calculate the <u>molar mass</u> to convert the moles to grams. For this we have to know the <u>atomic mass</u> of each atom:

Li ( 6.94 g/mol)

N (14 g/mol

O (16 g/mol)

With these values and the number of atoms in the molecule we can do the math:

(6.94 x 1) + ( 14 x 1) + (16 x 3 ) = 68.94 g/mol

The final step is the <u>calculation of the grams</u>, so:

0.268~mol~LiNO_3~\frac{69.94~g~LiNO_3}{1~mol~LiNO_3}=~18.5~g~LiNO_3

<u>We will need 18.5 g of LiNO3 to do a 0.783 M solution with a volume 342.6 mL.</u>

4 0
3 years ago
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