Answer:
Lowering the temperature typically reduces the significance of the decrease in entropy. That makes the Gibbs Free energy of the reaction more negative. As a result, the reaction becomes more favorable overall.
Explanation:
In an addition reaction there's a decrease in the number of particles. Consider the hydrogenation of ethene as an example.
.
When 
is added to 
(ethene) under heat and with the presence of a catalyst, 
(ethane) would be produced.
Note that on the left-hand side of the equation, there are two gaseous molecules. However, on the right-hand side there's only one gaseous molecule. That's a significant decrease in entropy. In other words, 
.
The equation for the change in Gibbs Free Energy for a particular reaction is:
.
For a particular reaction, the more negative 
is, the more spontaneous ("favorable") the reaction would be.
Since typically for addition reactions, the "entropy term" of it would be positive. That's not very helpful if the reaction needs to be favorable.
(absolute temperature) is always nonnegative. However, lowering the temperature could help bring the value of
Answer:
0.155836449023405
Explanation:
The molecular formula for Methane is CH4.
The SI base unit for amount of substance is the mole.
1 grams Methane is equal to 0.062334579609362 mole.
Effect of Hybridisation on Single, Double and Triple Bond Lengths of Carbon. Since the sp hybrid orbital contains more s-character (50%), it is closer to its nucleus; therefore, it forms shorter bonds. Because of the same reason sp2 hybrid orbital forms shorter bonds than sp3 hybrid orbitals.
Answer:
The right choice is CHCl₃
Explanation:
- <u>To find the empirical formula firstly, change the mass to moles.</u>
For Carbon :
no. of moles = (mass / molar mass) = (5.03 g / 12 g/mol )= 0.42 mol
<u><em>For Hydrogen :</em></u>
no. of moles = (mass / molar mass) = (0.42 g / 1 g/mol )= 0.42 mol
<u><em>For Chlorine :</em></u>
no. of moles = (mass / molar mass) = (44.5 g / 35.5 g/mol )= 1.25 mol
The ratio for Carbon and Hydrogen is 1 : 1
0.42 mol / 042 mol =1.00
- <u>
Then find a ratio between the moles.
</u>
The ratio of Chlorine to both Carbon and Hydrogen is 3:1
1.25 mol / 0.42 mol = 2.98 ≅ 3
So the ratio is 1 C : 1 H : 3 Cl.
So, the right choice is CHCl₃
Carbon usually forms four bonds one to Hydrogen and 3 to Chlorine atoms.
Chlorine usually forms one bond to Carbon atom.
Hydrogen usually forms one bond Carbon atom.
