PLEASE HELP i dont know how to do this show the work please

. Given ????(5, −4) and T(−8,12):

damaskus [11]

Answer:

a) $y=\dfrac{13x}{16}-\dfrac{129}{16}$

b) $y = \dfrac{13x}{16}+ \dfrac{37}{2}$

Step-by-step explanation:

Given two points: $S(5,-4)$ and $T(-8,12)$

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: $y = mx + c$ where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST we first need to find the gradient of ST, using the gradient formula.

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

$m = \dfrac{12 - (-4)}{(-8) - 5}$

$m = \dfrac{-16}{13}$

to find the perpendicular of this gradient: we'll use:

$m_1m_2=-1$

both $m_1$ and $m_2$ denote slopes that are perpendicular to each other. So if $m_1 = \dfrac{12 - (-4)}{(-8) - 5}$ , then we can solve for $m_2$ for the slop of ther perpendicular!

$\left(\dfrac{-16}{13}\right)m_2=-1$

$m_2=\dfrac{13}{16}$ :: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope $m$ and the points $(x,y)$ . And plug into the equation: $(y - y_1) = m(x-x_1)$

side note: you can also use the $y = mx + c$ to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

$(y - y_1) = m(x-x_1)$

we have the slope of the perpendicular to ST i.e $m=\dfrac{13}{16}$

and the line should pass throught S as well, i.e $(5,-4)$ . Plugging all these values in the equation we'll get.

$(y - (-4)) = \dfrac{13}{16}(x-5)$

$y +4 = \dfrac{13x}{16}-\dfrac{65}{16}$

$y = \dfrac{13x}{16}-\dfrac{65}{16}-4$

$y=\dfrac{13x}{16}-\dfrac{129}{16}$

this is the equation of the line that is perpendicular to ST and passes through S

a) Line through T and Perpendicular to ST

we'll do the same thing for $T(-8,12)$

$(y - y_1) = m(x-x_1)$

$(y -12) = \dfrac{13}{16}(x+8)$

$y = \dfrac{13x}{16}+ \dfrac{104}{16}+12$

$y = \dfrac{13x}{16}+ \dfrac{37}{2}$

this is the equation of the line that is perpendicular to ST and passes through T

7 0

3 years ago

Consider the following two loans for P=$12,000.

n200080 [17]

Answer:

Simple interest-?

Step-by-step explanation:

P= 12000

T=5yrs

R=5%

Now,

Simple interest - PTR/100

= 12000*5*5/100

= $3000

Again,

P=12000

T=3yrs

R=8%

Now,

Simple interest - PTR/100

= 12000*3*8/100

= $2880

Hope this helps.

4 0

2 years ago

What is the value of x in the equation below? -3-(-8)-(-2) = x O-13 O9 O 3 O 7

posledela

Answer:

7

Step-by-step explanation:

4 0

3 years ago

In order for the function to be linear, what must a be and why?

pochemuha

Answer:

213

Step-by-step explanation:

213

8 0

3 years ago

Multiply and simplify the product.

lianna [129]

Multiplying complex numbers is a lot like multiplying binomial terms. The only relation one has to remember when dealing with complex numbers is that i² = -1.

Now let us try to multiply binomials. This is done by adding the products of the first term of the first binomial distributed to the second binomial, and the second term of the first binomial distributed to the second binomial. This is done below:

(3 – 5i)(–2 + 4i) = -6 + 12i + 10i -20i²

Simplifying and applying i² = -1:
-6 + 22i - 20(-1)
-6 + 22i + 20
14 + 22i

Among the choices, the correct answer is B.

5 0

3 years ago

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