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vfiekz [6]
3 years ago
8

The first charge is pulling on the second. Is the second pulling on the first? Explain your reasoning

Physics
1 answer:
Alex73 [517]3 years ago
7 0

Answer:

law of action and reaction.

Explanation:

In Newton's three laws it is established that forces act in pairs, if one body interacts with another the second interacts with the first, this is the so-called law of action and reaction.

In this case, when the first load pulls on the second, the second pulls on the first, the two forces are not canceled because each one is applied to a different body.

Therefore the magnitude of the forces is the same, but the direction is opposite and each one is applied in a body

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A conductor is made in the form of a hollow cylinder with inner and outer radii a and b, respectively. It carries a current I, u
Nadusha1986 [10]

A conductor is made in the form of a hollow cylinder with inner and outer radii a and b, respectively. It carries a current I, uniformly distributed over its cross section. We are given that

  • Inner radius,
  • Outer radius,
  • Current=I
  • a.If r<a

Consider a loop of radius r where r<a

<h3>What is conductor?</h3>

A conductor is an object or kind of material that permits the movement of charge (electric current) in one or more directions. This term is used in both physics and electrical engineering. Metal-based materials are frequently used as electrical conductors. Negatively charged electrons, positively charged holes, and occasionally positive or negative ions flow to create electric current.

It is not essential for one charged particle to move from the component creating the current (the current source) to those consuming it for current to flow within a closed electrical circuit (the loads). Instead, the charged particle only needs to nuzzle its neighbor a limited number of times, and then the process repeats itself until a particle gets nuzzled into the consumer, generating electricity.

To learn more about conductor from the given link:

brainly.com/question/2290351

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4 0
1 year ago
A ball that is dropped will hit the ground at the same time as a ball that is thrown horizontally with an initial velocity of 2
Natali5045456 [20]

True: the time of flight of the two balls is the same

Explanation:

The ball that is dropped is in free fall, so its time of flight can be determined by using the suvat equation

s=ut+\frac{1}{2}at^2

where

s=h is the vertical displacement, which is the height from which it was dropped

u = 0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration of gravity

t is the time of flight

Solving for t,

t=\sqrt{\frac{2h}{g}}

The ball thrown horizontally follows a projectile motion, which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

However, the time of flight is completely determined by the vertical motion only, therefore using the equation:

s=ut+\frac{1}{2}at^2

where u = 0 is the initial vertical velocity of the ball (which is zero, since it is thrown horizontally). Since the ball is thrown from the same height, its time of flight is still

t=\sqrt{\frac{2h}{g}}

So, the two balls reach the grund at the same time.

Learn more about free fall and projectile motion:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

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5 0
4 years ago
A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on
MAXImum [283]

Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

Ec=\frac{1}{2} *m*v^{2}

where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).

The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:

W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}

W=\frac{1}{2} *m*(v2^{2}-v1^{2})

In this case:

  • W=?
  • m= 2,145 kg
  • v2= 12 \frac{m}{s}
  • v1= 25 \frac{m}{s}

Replacing:

W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})

W= -515,872.5 J

<u><em>The work required is -515,872.5 J</em></u>

3 0
3 years ago
What's the answer plz help?!
eimsori [14]
I think the answer is c chemical change
6 0
3 years ago
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1) if you could eliminate one item from your diet to improve your heath, what would it be?
Makovka662 [10]

Answer:

Rice

Explanation:

Because I can't control eating lots of rice

3 0
3 years ago
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