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3 years ago

Please help, thank you to anyone who answers! Will mark brainliest, give a thanks and a 5 star.

Physics

1 answer:

skelet666 [1.2K]3 years ago

6 0

Answer:

it is 2

Explanation:

Hydrogen atoms have one proton and one electron, thus, in order to fill the oxygen atom orbital to a full outer shell, a maximum of 2 atoms could bond with the oxygen atoms.

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Please help me answer this question I will be given the brainliest as well

Sophie [7]

draw a horizontal straight line from 25 to 75 and connects the line drawn at 75 to the bottom of the graph (0) at 90 with a straight line

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3 years ago

A heavy ball with a weight of 100 NN is hung from the ceiling of a lecture hall on a 4.4-mm-long rope. The ball is pulled to one

allochka39001 [22]

Answer:

175.3 N

Explanation:

The motion of the ball is a uniform circular motion, therefore the net force on it must be equal to the centripetal force.

There are two forces acting on the ball at the lowest point of motion:

- The tension in the string, T , upward

- The weight of the ball, $mg$ , downward

The net force (centripetal force) has the same direction as the tension (upward, towards the centre of the circular path), so we can write:

$T-mg=m\frac{v^2}{r}$

where the term on the right is the expression for the centripetal force, and where:

T is the tension in the string

$mg=100 N$ is the weight of the ball

$m=\frac{mg}{g}=\frac{100}{9.8}=10.2 kg$ is the mass of the ball

v = 5.7 m/s is the speed of the ball at the lowest point

r = 4.4 m is the length of the rope, so the radius of the circle

Solving for T, we find the tension in the string:

$T=mg+m\frac{v^2}{r}=(100)+(10.2)\frac{5.7^2}{4.4}=175.3 N$

7 0

3 years ago

A student wants to determine the effect of mass on kinetic energy. She will drop two balls of the same size into a pool of water

Anastasy [175]

Answer:

She should drop two balls with different masses from the same height

Explanation:

4 0

2 years ago

A pen rolls off a 0.55–meter high table with an initial horizontal velocity of 1.2 meters/second. At what horizontal distance fr

NARA [144]

To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation.

Y=Yo+Voyt+1/2at^2
0=.55+0+1/2(-9.8)t^2
-.55=-4.9t^2
sqrt(.55/4.9)=t
t=0.335 seconds

Horizontal distance
=0.335s*1.2m/s
=0.402 meters

8 0

3 years ago

Two horses are pulling a box in two different directions as shown in the below image. The image shows one 30.0 N force due north

Novay_Z [31]

Explanation:

'What is the magnitude of the force needed to stop the horses and bring the box into equilibrium?' ≈42N; according to the vectors rules.

'Where would you locate the rope to apply the force?' - in point D.

PS. zoom out the attached picture.

4 0

3 years ago