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3 years ago

If object A has more mass than object B, what will object A need to accelerate at the same rate as object B?

Physics

1 answer:

Leni [432]3 years ago

3 0

Answer:

More force

Explanation:

Object A has more mass than object B

For object A to accelerate at the same rate as object B, it will need more force.

According to Newton's second law of motion "the net force on a body is the product of its mass and acceleration".

Net force = mass x acceleration

Now, if a body has more mass and needs to accelerate at the same rate as another one with a lower mass, the force on it must be increased.

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Which situation is the best example of translational motion?.

AleksAgata [21]

Answer:

a block sliding down a ramp,a leaf blowing across a field

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2 years ago

A spring has a spring constant of 330 n/m. how far is the spring compressed when 150 newtons of force are used?

pishuonlain [190]

Answer:

I think its B

Explanation:

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3 years ago

Which sentence from the article supports the idea that the visible spectrum is more limited in marine animals than humans? A Mos

lidiya [134]

Most marine bioluminescence is blue-green, which is easier to see in the deep ocean

Explanation:

As per science, Emission and production of light by a living organism is defined as Bioluminescence. Bioluminescence occurs widely in marine animals whereas it is triggered by a physical disturbance is seen by humans, such as a moving boat hull or waves.

Throughout the water column bioluminescent organisms live and bioluminescence is extremely common in deep sea which shows that visible spectrum is more limited to marine animals than humans.

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3 years ago

A long, straight metal rod has a radius of 5.75 cm and a charge per unit length of 33.3 nC/m. Find the electric field at the fol

PIT_PIT [208]

Answer:

Explanation:

From the question;

We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.

We are to calculate the following task, i.e. to determine the electric field at the distances:

a) at 4.75 cm

b) at 20.5 cm

c) at 125.0 cm

Given that:

the charge (q) = 33.3 nC/m

= 33.3 × 10⁻⁹ c/m

radius of rod = 5.75 cm

a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.

Then, the electric field will be zero.

b) The electric field formula $E = \dfrac{kq }{d}$

$E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{0.205}$

E = 1461.95 N/C

c) The electric field E is calculated as:

$E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{1.25}$

E = 239.76 N/C

7 0

3 years ago

You throw a rock horizontally out of a 7th story window. You time that it takes 3.7 seconds to hit the ground, and measure that

Nady [450]

Since we are only looking at the vertical height, we can use the free fall equation to find the height:
h = 0.5*g*t^2, where h is height in m, g is acceleration due to gravity (9.81 m/s^2), and t is time in seconds
h = 0.5*(9.81 m/s^2)*(3.7 s)^2
h = 67.15 m
Therefore, the 7th floor window is 67.15 m above ground level.

5 0

3 years ago