270 / 3 ( (4 - 3) 3 - (-9) ) - 53
270 / 3 (1 x 3 - (-9) ) - 53
270 / 3 (3 + 9) - 53
270 / 3 x 12 - 53
In PEMDAS, with multiplication and division, you must go left to right, not multiplication then division.
90 x 12 - 53
1080 - 53
1027 is your answer
A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.
yikes i remember doing this but.... i completely forgot ;–; i really wish i could help
7 and 8 because 52 is between 49 and 64