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erma4kov [3.2K]
3 years ago
9

Cells can regulate different processes in two ways. They can turn on and off the genes that make enzymes, or they can

Chemistry
1 answer:
Anna11 [10]3 years ago
3 0
B.
Increase the amount of energy needed to carry out preferred process
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The element in period 3 with the most metallic character is A sodium
Gekata [30.6K]
A. Sodium is correct.

Sodium is an alkali metal.
Aluminum is a post-transitional metal- still a metal but it’s character is not as metallic as sodium.
Silicon is a metalloid- it has characteristics from both the metals and the non-metals.
Phosphorous is a non-metal.
8 0
3 years ago
I need help with this question please!!
mariarad [96]
The answer is B

Hope this helped. Good luck!
3 0
3 years ago
What does the latent heat of fusion represent?
sergey [27]

Answer:

this option is correct the amount of heat required to turn a mole of a solid into a liquid

7 0
3 years ago
Read 2 more answers
What is the mass of the object?
galben [10]

Answer:

37.3

263.5

Explanation:

The scale measures hundreds of units, tens of units, units, and parts of units (1 decimal place.

Scale 1

Hundreds 0 * 100 = 0

Tens: 3 * 10 = 30

Units: 7 * 1 = 7

1/10 unit = 3* 0.1 = 0.3

Total 30 + 7 + 0.3 = 37.3

Scale 2

Hundreds 2 * 100 = 200

Tens: 6 * 10 = 60

Units: 3 * 1 = 3

1/10 unit = 5* 0.1 = 0.5

Total = 200 + 60 + 3 + 0.5 = 263.5

7 0
3 years ago
A compound that is composed of molybdenum (Mo) and oxygen (O) was produced in a lab by heating molybdenum over a Bunsen burner.
irakobra [83]
First, we determine the mass of each element from the data collected. We can get the mass of molybdenum Mo from the difference between the mass of crucible and molybdenum and the mass of crucible:
     Mass of molybdenum = 39.52 – 38.26 = 1.26 g Mo

We can calculate for the mass of molybdenum oxide from the difference between the mass of crucible and molybdenum oxide and the mass of crucible:
     Mass of molybdenum oxide = 39.84 – 38.26 = 1.58g 

We can now compute for the mass of oxygen O by subtracting the mass of molybdenum from the mass of molybdenum oxide:
     Mass of oxygen in molybdenum oxide = 1.58 – 1.26 = 0.32g O

To convert mass to moles, we use the molar mass of each element.
     1.26 g Mo * 1 mol Mo / 95.94 g Mo = 0.0131 mol Mo
     0.32 g O * 1 mol O / 15.999 g O = 0.0200 mol O

0.0131 mol is the smallest number of moles. We divide each mole value by this number:
     0.0131 mol Mo / 0.0131 = 1
     0.0200 mol O / 0.0131 = 1.53

Multiplying these results by 2 to get the lowest whole number ratio,
     0.0131 mol Mo / 0.0131 = 1 * 2 = 2
     0.0200 mol O / 0.0131 = 1.5 * 2 = 3
Thus, we can write the empirical formula as Mo2O3.
5 0
3 years ago
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