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lyudmila [28]
3 years ago
12

How many moles are present in 356.4 g of NiBr3

Chemistry
1 answer:
lozanna [386]3 years ago
8 0

1.194 mol

(remember to use sig figs!)

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A molecule contains 47.30 g mercury (Hg) and 16.70 (Cl). what is its empirical formula?
Bogdan [553]
Answer: B) HgCl2

Explanation:

Convert grams to moles for both elements by dividing the mass by it’s molar mass (Mr).
Hg- 47.30/201= 0.23 mols
Cl- 16.70/35= 0.47 mols

Now, divide the moles of both elements with the smallest number. The smallest number here is 0.23.
Hg- 0.23/0.23= 1
Cl- 0.47/0.23= 2.04 (since there is a 0 after the decimal we will forget the decimal and write the number as a whole.)

Empirical Formula= Hg1Cl2

6 0
2 years ago
What are two examples of objects with low friction?
Naily [24]

Answer:

A washing machine pushed along a floor.

An iron being pushed across material.

6 0
4 years ago
Через 100 мл одномолярного раствора гидроксида натрия пропустили 896 мл (н.у.) углекислого
fgiga [73]
Yes it is right sir or ma’am
6 0
3 years ago
What is the density of an object having a mass of 16 g and a volume of 30 mL ?
Marizza181 [45]

Answer:

12

Explanation:

7 0
3 years ago
Read 2 more answers
3. If 45.0 mL of 0.560 M KOH are needed to neutralize 125 mL of HCl of unknown concentration, what is
vlada-n [284]

Answer:

Molarity = 0.202 M

7.36 g/L HCl

Explanation:

KOH                        +                  HCl ----> KCl  +  H2O

1 mol                                           1 mol

0.560mol/L *0.045L                 x mol/L*0.125L

0.560mol/L *0.045L    =   x mol/L*0.125L

x = 0.560mol/L *0.045L  /0.125L= 0.2016 mol/L≈ 0.202 mol/L=0.202M HCl

M(HCl) = 1.0+35.5 = 36.5 g/mol

0.2016 mol/L*36.5 g/mol ≈ 7.36 g/L HCl

6 0
4 years ago
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