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zhuklara [117]
3 years ago
6

Jack, a student, travels to school 10 miles every morning. The speed limit is 25 miles/hour. How long it takes Jack to get to hi

s school?
Physics
2 answers:
taurus [48]3 years ago
8 0

Answer:

24 minutes

Explanation:

• If the speed limit is 25miles/hour, it takes 2.4 minutes to travel 1 mile.

60mins/25miles

= 2.4 minutes

• Therefore to travel 10 miles;

2.4 minutes × 10

= 24 minutes

Stells [14]3 years ago
6 0

Answer:

0.4 hour or 24 minutes

Explanation:

Speed =displacement /time

25miles/hour=10/time

10/25=time

0.4hour=time

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Answer:

move upward with increasing speed

I draw fbd diagram , see in figure

when lift going upward -

F - mg = ma

f = m( a + g)

scale so highest reading

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4 years ago
If you were to study the cephalic region of the
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Answer:

the standard way the body is positioned when using anatomical terminology ... invisible line that runs vertically through the center of the axial region.

Explanation:

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3 years ago
A motorboat approaches you head-on and sounds one short blast. how do you signal that you agree to let it pass on your port (lef
nadya68 [22]
The blast made by the vessel's driver is telling you that he intends to pass by your left side. If you agree with his intention, you will respond by sounding one short blast in return. If you are not in agreement with this move or you do not really understand the intention of the driver, you will give the danger signal which is five short rapid blasts.
6 0
3 years ago
Richard is driving home to visit his parents. 150 mi of the trip are on the interstate highway where the speed limit is 65 mph .
Serggg [28]

Answer:

t = 25.5 min

Explanation:

To know how many minutes does Richard save, you first calculate the time that Richard takes with both velocities v1 = 65mph and v2 = 80mph.

t_1=\frac{x}{v_1}=\frac{150mi}{65mph}=2.30h\\\\t_2=\frac{x}{v_2}=\frac{150mi}{80mph}=1.875h

Next, you calculate the difference between both times t1 and t2:

\Delta t=t_1-t_2=2.30h-1.875h=0.425h

This is the time that Richard saves when he drives with a speed of 80mph. Finally, you convert the result to minutes:

0.425h*\frac{60min}{1h}=25.5min=25\ min\ \ 30 s

hence, Richard saves 25.5 min (25 min and 30 s) when he drives with a speed of 80mph

3 0
3 years ago
What must be the distance between point charge q1 = 28.0 μC and point charge q2 = −57.0 μC for the electrostatic force between t
vlabodo [156]

Answer:

1.686 m

Explanation:

From coulomb's law,

F = kq1q2/r² ...................................... Equation 1

Where F = electrostatic force  between the two charges, q1 = first charge, q2 = second charge, r = distance between the charges.

making r the subject of the equation,

r = √(kq1q2/F).......................... Equation 2

Given: F = 5.05 N, q1 = 28.0 μC = 28×10⁻⁶ C, q2 = 57.0 μC = 57.0×10⁻⁶ C

Constant: k = 9.0×10⁹ Nm²/C².

Substituting into equation 2

r = √(9.0×10⁹×28×10⁻⁶×57.0×10⁻⁶/5.05)

r = √(14364×10⁻³/5.05)

r = √(14.364/5.05)

r = √2.844

r = 1.686 m

r = 1.686 m.

Thus the distance must be 1.686 m

6 0
3 years ago
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