Yes that is correct. We know this because 4.00 x 10 4 Pa is constant. If you have 2.00×10−3m3 then you do the following: (2.00×10^−3)(4.00×10^<span> 4) = </span>8.00×10^−3. That is how you get your answer
Answer:
W = 55.12 J
Explanation:
Given,
Natural length = 6 in
Force = 4 lb, stretched length = 8.4 in
We know,
F = k x
k is spring constant
4 = k (8.4-6)
k = 1.67 lb/in
Work done to stretch the spring to 10.1 in.
![W = \dfrac{k}{2}[x^2]_6^{10.1}](https://tex.z-dn.net/?f=W%20%3D%20%5Cdfrac%7Bk%7D%7B2%7D%5Bx%5E2%5D_6%5E%7B10.1%7D)
W = 55.12 J
Work done in stretching spring from 6 in to 10.1 in is equal to 55.12 J.
Answer: Honestly miss im not sure but i am pretty sure it is The HYDROSPHERE AND THE GEOSPEHER. I figured it out. Pls give me brainlest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Explanation:
The photosynthesis equation is :
H2O + CO2 + sunlight (energy) > C6H12O6 + O2
So water (H2O) and carbon dioxide (CO2) are the raw materials need for photosynthesis.
Hmmm. I think the answer is A. If I remember correctly. I had this question before. Sorry if I'm wrong.
