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Maksim231197 [3]
2 years ago
10

If you were to study the cephalic region of the

Physics
1 answer:
devlian [24]2 years ago
3 0

Answer:

the standard way the body is positioned when using anatomical terminology ... invisible line that runs vertically through the center of the axial region.

Explanation:

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Neko [114]

Answer:

the answer is C.

Explanation:

6 0
3 years ago
HOW TO DO THIS QUESTION PLEASE ​
allsm [11]
For figure one the “+” are protons and the “-“ are electrons for the second one the middle is the nucleus and the other is the orbit
7 0
2 years ago
You want a special device to keep coffee warm what type of electromagnetic waves would be useful
fredd [130]
Microwaves at the specific frequency where vibrates water molecules

Or

Infrared waves is the other name for heat
8 0
3 years ago
- What is the total distance traveled by the car
slega [8]

*Graph is attached with the answer*

Answer:

Total distance traveled by the car is 40 m

Explanation:

It can be seen from the graph that for the first 4 second car is moving with uniform acceleration and for next 2 second it has constant velocity

So, we solved this question in 2 parts

Part 1:

               initial velocity = v₁ = 0 m/s

               final velocity = v₂ = 10 m/s

                time = t = 4 s

                acceleration = a = (v₂ - v₁)/t

                                a = 10/4 = 2.5 m/s²

Using 3rd equation of motion

                2as = v₂² - v₁²

                 2(2.5)s = 10²

                      s₁ = 100/5

                     s₁ = 20 m

Part 2:

            s₂ = v₂t

            s₂ = 10 × 2

            s₂ = 20 m

Total distance = S = s₁ + s₂

                              = 20 + 20

                          S = 40 m

7 0
3 years ago
A pilot wants to fly on a bearing of 74.9 degrees. By flying due east, he find s that a 42-mph wind, blowin from the south, puts
hichkok12 [17]
The bearing shows the angle from north to the line (c), you want to see the angle inside the triangle so that will be 90-[bearing]. 

<span>a=42 (42 mph wind blowing north) </span>

<span>A= 90-74.9 </span>
<span>A= 15.1 degrees </span>

<span>Ground speed is the speed the plane is going including the wind. </span>
<span>ground speed = c </span>
<span>Airspeed = b </span>

<span>You have the angle, and you have the "Opposite" and want to find the "Hypotenuse". </span>
<span>SOH CAH TOA </span>

<span>Sin x = Opp/Hypot </span>

<span>Sin(15.1) = 42/c </span>
<span>c = 42/Sin(15.1) </span>
<span>c = 161.53 </span>

<span>Ground speed of the plane is 161.53 mph </span>

<span>Airspeed = b </span>

<span>Tan x = Opp/Adj </span>
<span>Tan (15.1) = 42/b </span>
<span>b = 42/Tan(15.1) </span>
<span>b = 161.53 </span>

<span>Airspeed = 161.53 mph </span>

<span>(so the answer is ground speed of 161.53mph)</span>
3 0
3 years ago
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