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kozerog [31]
2 years ago
11

A rock is thrown down from the top of a cliff with a velocity of 3.61 m/s (down). The cliff is 28.4 m above the ground. Determin

e the velocity of the rock just before it hits the ground.
Physics
1 answer:
Katarina [22]2 years ago
4 0
I’m not sure look it up in the internet!
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I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?
Ulleksa [173]

Answer:

<em>B. 68.6m</em>

Explanation:

<u>Free Fall Motion </u>

When a body is left to move in the air with no friction, the motion is ruled only by the force of gravity. The vertical distance a body travels in the air after a time t is .

\displaystyle y=\frac{gt^2}{2}

We know the egg takes 3.74 seconds to reach the ground. The height it was launched from is

\displaystyle y=\frac{(9.8)(3.474)^2}{2}

\displaystyle y=68.54\ m

The closest correct option is

B. 68.6m

5 0
3 years ago
Use the fact that 1inch=2.54cm and convert 52 inches into the equivalent length in centimeters.
Lelu [443]

Answer:

To convert inches to centimeters, use an easy formula and multiply the length by the conversion ratio.

Since one inch is equal to 2.54 centimeters, this is the inches to cm formula to conver

Explanation:

4 0
2 years ago
A capacitor with a capacitance of 50µf when connected to a battery of 400 V. The charge and energy stored on it is? a. 0.05 C an
nekit [7.7K]

Answer:

c. 0.02 C and 4 J

Explanation:

Applying,

Q = CV................ Equation 1

Where Q = Charge, C = Capacitance of the capacitor, V = Voltage.

From the question,

Given: C = 50 μF = 50×10⁻⁶ F, V = 400 V

Substitute these values into equation 1

Q = (50×10⁻⁶)(400)

Q = 0.02 C.

Also Applying

E = CV²/2............. Equation 2

Where E = Energy stored.

Therefore,

E = (50×10⁻⁶ )(400²)/2

E = 4 J

Hence the right option is c. 0.02 C and 4 J

3 0
2 years ago
Stars on the left of the diagram above are (View the picture to see the diagram)
omeli [17]

<em>D. Less luminous than those on the right []</em>

4 0
3 years ago
Read 2 more answers
A small candle is 38 cm from a concave mirror having a radius of curvature of 24 cm. (a) what is the focal length of the mirror?
Finger [1]
For a concave mirror, the radius of curvature is twice the focal length of the mirror:
r=2f
where f, for a concave mirror, is taken to be positive.

Re-arranging the formula we get:
f= \frac{r}{2}
and since the radius of curvature of the mirror in the problem is 24 cm, the focal length is
f= \frac{24 cm}{2} = 12 cm

8 0
3 years ago
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