Apply the law of conservation of momentum for this situation. The law states that the momentum of a system is constant (in absence of external forces acting on it).
The 'system' in this case are the two skaters. There is no external force on the skaters. Suppose the skaters are initially standing still. The momentum in the system is 0. This value will need to remain constant, even after the mutual push (which is a set of forces from <em>inside</em> the system). So we know that
(total momentum before) = (total momentum after)
Indexing the masses and velocities by the first letter of the skaters' names:
From the last row, you can see that the skaters will have momentum of same magnitude but opposite direction, after the push off. That answers the first question: neither will have a greater momentum (both will have one of same magnitude).
Since Ricardo is heavier, from the above equality it follows that
In words, Paula has the greater speed, after the push-off.
The value of the c will be (0 i+0 j+0 k). c is a vector that is along the positive x-axis and has the condition a(b+c)=0.
<h3>What is a vector?</h3>
A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.
Given ;
a=3i-2j+k
b=-i-4j+3k
Given property:
a(b+c)=0
-i-4j+3k ((-i-4j+3k)+c)=0
(3+8+3)(-i-4j+3k)c=0
14(-i-4j+3k)c=0
c=0 i+0 j+0 k
Hence, the value of the c will be (0 i+0 j+0 k).
To learn more about the vector refer to the link;
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Answer:
The answer to your question is W = 3695464.4 J
Explanation:
Mechanical work is the force applied to an object multiply by the distance this object move as a consequence of the force.
Formula
Work = W (J)
Force = F (N)
distance = d (m)
W = F x d
Substitution
F = 6818.2 N
d = 542 m
W = 6818.2 x 542
Simplification and result
W = 3695464.4 J
The kinetic energy of the bullet is 20.4 kJ.
<u>Explanation:</u>
Kinetic energy of a bullet will be equal to the product of mass of the bullet with the square of velocity or speed of the bullet and then the half of that product value.
But here the mass of the bullet is not given, instead the weight of the bullet is given in terms of force. So from this, we have to first find the mass of the bullet.
We know that as per Newton's second law of motion, force is directly proportional to the product of mass and acceleration. So here the acceleration will be equal to the acceleration due to gravity as it is weight of the object.
So F = mg
0.10 N = m × 9.8
So ,the mass of the bullet is 0.0102 kg.
Now, we know the mass and velocity of the bullet is given as 2000 m/s.
So,
kinetic energy = 
× m × v²
kinetic energy = 0.5 × 0.0102 × 2000 × 2000 = 20.4 kJ
Thus, the kinetic energy of the bullet is 20.4 kJ.
The intensity is defined as the ratio between the power emitted by the source and the area through which the power is calculated:
(1)
where
P is the power
A is the area
In our problem, the intensity is
. At a distance of r=6.0 m from the source, the area intercepted by the radiation (which propagates in all directions) is equal to the area of a sphere of radius r, so:
And so if we re-arrange (1) we find the power emitted by the source:
