C is the correct answer but the best possible answer is that work is done when a force is imposed on an object and the object moves in the same direction as the force
Hope this helps!
Answer: hello options related to your question is missing attached below is the missing part of your question
answer: No charge of the length of the bonds expected because the rod did not touch the charge source ( option A )
Explanation:
When the Charge is first, Furthest away and second and closest to the source charge. <em>The spring like bonds can be said to have No charge of the length of the bonds expected because the rod did not touch the charge source </em><em>when Furthest away the bond with charge will be less effective </em>
Answer:
Thrust = 200 N
Explanation:
The engine thrust can be found by using the following formula:
where,
m = mass flow rate of the fuel = 0.05 kg/s
v = velocity of ejected gases = 4000 m/s
Therefore, using the given values in the equation, we get:
<u>Thrust = 200 N</u>
Answer:
a rock of 50kg should be placed =drock=0.5m from the pivot point of see saw
Explanation:
τchild=τrock
Use the equation for torque in this equation.
(F)child(d)child)=(F)rock(d)rock)
The force of each object will be equal to the force of gravity.
(m)childg(d)child)=(m)rockg(d)rock)
Gravity can be canceled from each side of the equation. for simplicity.
(m)child(d)child)=(m)rock(d)rock)
Now we can use the mass of the rock and the mass of the child. The total length of the seesaw is two meters, and the child sits at one end. The child's distance from the center of the seesaw will be one meter.
(25kg)(1m)=(50kg)drock
Solve for the distance between the rock and the center of the seesaw.
drock=25kg⋅m50kg
drock=0.5m
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
(0.15 x g)/100 = 0.0147N. per cm. length.
<span>Torque short end = (0.0147 x 9) = 0.1323N/cm. </span>
<span>Torque long end = ((100 - 18)/2) x 0.0147 = 0.6027N/cm. </span>
<span>Difference = (0.6027 - 0.1323) = 0.4704N/cm. </span>
<span>(0.4704/3.2) = 0.147cm. from the 18cm. mark, = 17.853cm. from the 0 end of the stick.</span>
