Find BC if B (8,-7) and C (-4,-2)
1 answer:
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We are given polynomial: .
We need to explain why the binomial (x + 2) IS a factor of this polynomial expression and why the binomial (x + 1) IS NOT a factor of this polynomial expression.
Let us set first factor equal to 0 and solve for x.
x+2=0
x=-2.
Plugging x=-2 in given polynomial, we get
<em>Because x=-2 gives 0 on plugging in given polynomial, so it's factor of given polynomial expression.</em>
Now, let us check second factor x+1=0
x=-1.
Plugging x=-1 in given polynomial, we get
=-5+8+7-6.
= -4.
<em>Because x=-1 doesn't gives 0 on plugging in given polynomial, so it's not a factor of given polynomial expression.</em>
Answer:
Step-by-step explanation:
Given
x - = 9 ← square both sides
(x - )² = 9²
x² - 2 + = 81 ( add 2 to both sides )
x² + = 83
Now
(x + )² = x² +
+ 2, thus
x² + = 83 + 2 = 85
(x + )²= 85 ( take the square root of both sides)
x + =