Question

3Fe + 4H2O ‐----> Fe3O4 + 4H2

Answer 1

The limiting reactant​ : Fe

Further explanation

Reaction

3Fe + 4H₂O ⇒ Fe₃O₄ + 4H₂

mass of H₂O = 10 g

mol H₂O (MW=18 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{10}{18}=0.56$

mass of Fe = 16.8 g

mol Fe(MW=56 g/mol) :

$\tt mol=\dfrac{16.8}{56}=0.3$

Limiting reactant : the smallest ratio between mol : reaction coefficient

Fe :

$\tt \dfrac{0.3}{3}=0.1$

H₂O :

$\tt \dfrac{0.56}{4}=0.14$

Fe as limiting reactant