Answer:
Q = 1.08x10⁻¹⁰
Yes, precipitate is formed.
Explanation:
The reaction of CoF₂ with NaOH is:
CoF₂(aq) + 2 NaOH(aq) ⇄ Co(OH)₂(s) + 2 NaF(aq).
The solubility product of the precipitate produced, Co(OH)₂, is:
Co(OH)₂(s) ⇄ Co²⁺(aq) + 2OH⁻(aq)
And Ksp is:
Ksp = 3x10⁻¹⁶= [Co²⁺][OH⁻]²
Molar concentration of both ions is:
[Co²⁺] = 0.018Lₓ (8.43x10⁻⁴mol / L) / (0.018 + 0.022)L = <em>3.79x10⁻⁴M</em>
[OH⁻] = 0.022Lₓ (9.72x10⁻⁴mol / L) / (0.018 + 0.022)L = <em>5.35x10⁻⁴M</em>
Reaction quotient under these concentrations is:
Q = [3.79x10⁻⁴M] [5.35x10⁻⁴M]²
<em>Q = 1.08x10⁻¹⁰</em>
As Q > Ksp, <em>the equilibrium will shift to the left producing Co(OH)₂(s) </em>the precipitate
Answer:
There is 17,114825 g of powdered drink mix needed
Explanation:
Step 1 : Calculate moles
As given, the concentration of the drink is 0.5 M, this means 0.5 mol / L
Since the volume is 100mL, we have to convert the concentration,
⇒0.5 / 1 = x /0.1 ⇒ 0.5* 0.1 = x = 0.05 M
This means there is 0.05 mol per 100mL
e
Step 2 : calculate mass of the powdered drink
here we use the formula n (mole) = m(mass) / M (Molar mass)
⇒ since powdered drink mix is usually made of sucrose (C12H22O11) and has a molar mass of 342.2965 g/mol.
0.05 mol = mass / 342.2965 g/mol
To find the mass, we isolate it ⇒0.05 mol * 342.2965 g/mol = 17,114825g
There is 17,114825 g of powdered drink mix needed
50.00ml*(10^-3L/ml)*(3.91moles/L) = 0.196 mol
Dalton's atomic theory proposed that all matter was composed of atoms, indivisible and indestructible building blocks. While all atoms of an element were identical, different elements had atoms of differing size and mass.
Both mass and weight are measured by using scales.
