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Lelu [443]
2 years ago
9

He electrostatic attraction between positively charged nuclei and negatively charged electrons permits two atoms to be held toge

ther by a(n)
Chemistry
1 answer:
Law Incorporation [45]2 years ago
7 0

Answer: chemical bond

Explanation:

The chemical bond simply refers to the electrostatic attraction that can be found between ions that are oppositely-charged. It should be noted that the chemical bond occurs due to the transfer of electrons that is being found between atoms.

Therefore, based on the question given, the electrostatic attraction that is seen between a positively charged nuclei and the negatively charged electrons which hence allows two atoms to be held together is the chemical bond.

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What volume will 20.0g of Argon occupy at STP?
Yuki888 [10]
Molar mass Argon = 39.948 g/mol

1 mol ------ 39.948 g
  mol ----- 20.0 g 

mol = 20.0 * 1 / 39.948

= 0.5006 moles

1 mol --------------------- 22.4 L ( at STP )
0.5006 moles ------------- L 

L = 0.5006 * 22.4

= 11.21 L

hope this helps!
6 0
2 years ago
Describe the double circulation system of the human body
Alika [10]

Answer:

we have two loops in our body in which blood circulates. One is oxygenated, meaning oxygen rich, and the other is deoxygenated, which means it has little to no oxygen, but a lot of carbon dioxide.

4 0
3 years ago
Put the level of organization in order from smallest to largest a. Organelles, cellsorgans, tissuesorgan systems b. Organs, tiss
Lesechka [4]

Answer: My guess is D i hope this is right

Explanation:

8 0
3 years ago
For a process Arightwards harpoon over leftwards harpoonB, at 25 °C there is 10% of A at equilibrium while at 75 °C, there is 80
Lostsunrise [7]

This question is describing the following chemical reaction at equilibrium:

A\rightleftharpoons B

And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:

K_1=\frac{90\%}{10\%}=9\\\\K_2=\frac{20\%}{80\%}  =0.25

Thus, by recalling the Van't Hoff's equation, we can write:

ln(K_2/K_1)=-\frac{\Delta H}{R}(\frac{1}{T_2} -\frac{1}{T_1} )

Hence, we solve for the enthalpy change as follows:

\Delta H=\frac{-R*ln(K_2/K_1)}{(\frac{1}{T_2} -\frac{1}{T_1} ) }

Finally, we plug in the numbers to obtain:

\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}

Learn more:

  • brainly.com/question/10038290
  • brainly.com/question/19671384
5 0
2 years ago
What's the difference between incomplete dominance and codominance
EastWind [94]
In total dominance, the phenotype sees only one allele in the genotype. Both alleles in the genotype are seen in the phenotype during codominance. In incomplete dominance, in the phenotype, a mixture of the alleles in the genotype is seen.
7 0
2 years ago
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