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Eduardwww [97]
3 years ago
10

Calculate the second volumes 980L at 71C and 107.2atm to 13C and 59.3atm

Chemistry
1 answer:
Lapatulllka [165]3 years ago
5 0

Answer:

V₂ = 1473.03 L

Explanation:

Given data:

Initial volume = 980 L

Initial pressure = 107.2 atm

Initial temperature = 71 °C (71 +273.15 = 344.15 K)

Final temperature = 13°C (13+273.15 = 286.15K)

Final volume = ?

Final pressure = 59.3 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 107.2 atm × 980L × 286.15 K / 344.15 K×   59.3 atm

V₂ = 30061774.4 atm .L. K / 20408.095 atm. K

V₂ = 1473.03 L

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Answer:

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Explanation:

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Answer:

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Explanation:

Step 1:

Data obtained from the question. This includes:

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Initial pressure (P1) = 600 mmHg

Initial temperature (T1) = 20°C

Final temperature (T2) = 15°C

Final volume (V2) = 90L

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Step 2:

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This is illustrated below:

T(K) = T (°C) + 273

Initial temperature (T1) = 20°C

Initial temperature (T1) = 20°C + 273 = 293K

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The new pressure of the gas can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

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Cross multiply to express in linear form

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Divide both side by 90 x 293

P2 = (600 x 70 x 288) / (90 x 293)

P2 = 458.7 mmHg

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