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Sergio [31]
4 years ago
15

Question 10

Chemistry
1 answer:
bixtya [17]4 years ago
5 0
The reaction that should be followed is
Na2SO4 + C<span>a(NO3)2 --> CaSO4 + 2NaNO3</span>
first calculate the limiting reactant
mol Na2SO4 = 0.075 L (<span>1.54×10−2 mol / L) = 1.155x10-3 mol


mol Ca(NO3)2 = 0.075 L (</span><span>1.22×10−2 mol / L) = 9.15x10-4 mol
so the limiting reactant is the Ca(NO3)2

so all of the Ca2+ will be precipitated, percentage unprecipitated = 0.00 % </span>



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We will take that molar mass of Pb(CO3)2 represents the total mass of all particles in this compound, ie it has value 100%.

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From the date above we can set the following ratio:

M(Pb(CO3)2) : M(Pb) = 100% : x

327.2 : 207.2 = 100 :x

x = 63.33% of Pb there is in <span>Pb(Co3)2</span>




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I hope this helps if not sorry :(

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