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Sergio [31]
4 years ago
15

Question 10

Chemistry
1 answer:
bixtya [17]4 years ago
5 0
The reaction that should be followed is
Na2SO4 + C<span>a(NO3)2 --> CaSO4 + 2NaNO3</span>
first calculate the limiting reactant
mol Na2SO4 = 0.075 L (<span>1.54×10−2 mol / L) = 1.155x10-3 mol


mol Ca(NO3)2 = 0.075 L (</span><span>1.22×10−2 mol / L) = 9.15x10-4 mol
so the limiting reactant is the Ca(NO3)2

so all of the Ca2+ will be precipitated, percentage unprecipitated = 0.00 % </span>



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The melting point of copper is 1084°C. How does the energy of the particles in a certain amount of liquid copper compare to the
ipn [44]
The melting point of the solid form of water, which is ice, is 0°C. When we convert both temperatures to kelvin by adding 273 to each we get the melting point of copper as 1357K and that of ice is 273K. Then, dividing the melting point of copper by the melting point of ice, both in absolute temperature scale. The answer would be 4.97. Thus, the energy of molecules of copper is approximately 5 times compared to that of water. 
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4 years ago
Balance this equation. if a coefficient of "1" is required, choose "blank" for that box.
blondinia [14]
Step 1: Write Imbalance Equation

                            CH₃CHO  +  O₂    →    CO₂  +  H₂O

Step 2: Balance Carbon Atoms:
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                             CH₃CHO  +  O₂    →    2 CO₂  +  H₂O 

Step 3: Balance Hydrogen Atoms:
                                                      There are 4 hydrogen atoms at reactant side and 2 Hydrogen atoms at product side. So, multiply H₂O by 2 to balance Hydrogen on both sides. i.e.

                    CH₃CHO  +  O₂    →    2 CO₂  +  2 H₂O

Step 4: Balance Oxygen Atoms:
                                                   There are 3 Oxygen atoms at reactant side and 6 Oxygen atoms at product side. In order to balance them multiply O₂ on reactant side by 2.5 (5/2). i.e  

                    CH₃CHO  +  5/2 O₂    →    2 CO₂  +  2 H₂O

Step 6: Eliminate Fraction:
                                         Multiply overall equation by 2 to eliminate fraction. i.e. 

                    2 CH₃CHO  +  5 O₂    →    4 CO₂  +  4 H₂O
7 0
3 years ago
An atom of boron has an atomic number of 5 and an atomic mass of 11. The atom contains
Liono4ka [1.6K]

Answer:

5 protons, 5 electrons, and 6 neutrons

3 0
3 years ago
Explain what interaction is in the hydrogen fluoride (HF) and hydrogen chlori de (H CI) Which one do you expect to have a higher
djyliett [7]

Explanation:  

Part A

Boiling point of HF is much higher as compared to the boiling point of HCl.

Reason:

The strongest inter molecular hydrogen bonding exist between HF molecules This is due to highly electronegative Fluorine atom.

Part B

The type of bonding present in the given compounds are:

1. Ice  

The water molecules in ice are linked to each other through intermolecular hydrogen bonding due to the presence of electronegative oxygen atom that is attached to hydrogen atom.

2. Copper dioxide

In  Copper dioxide, Copper and oxide ions are linked to each other via electrostatic force of attraction due to the presence of electronegative Oxygen atom and electropositive Cu atom.

Therefore, ionic bond is present in it.

3. Steel

In steel, metal and negatively charged electrons are linked to each other, thus giving rise to metallic bond between steel molecules.

4. Silicon elastomer

In silicon elastomer, Silicon atom is linked to other atom via covalent bonds due to sharing of electrons.

5. Tungsten

In the case of tungsten also, atoms are bonded to each other via metallic bond.

7 0
3 years ago
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Free_Kalibri [48]

Answer: The vapor pressure of methanol solution at 298K is 107.12 torr

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

\frac{p^o-p_s}{p^o}=i\times x_2

where,

\frac{p^o-p_s}{p^o}= relative lowering in vapor pressure

i = Van'T Hoff factor = 1 (for non electrolytes)

x_2 = mole fraction of solute  =\frac{\text {moles of solute}}{\text {total moles}}

Given : 38.5 g of urea is present in 142 g of methanol

moles of solute (urea) = \frac{\text{Given mass}}{\text {Molar mass}}=\frac{38.5g}{60g/mol}=0.64moles

moles of solvent (methanol) = \frac{\text{Given mass}}{\text {Molar mass}}=\frac{142g}{32g/mol}=4.4moles

Total moles = moles of solute  + moles of solvent  = 0.64 + 4.4 = 5.04

x_2 = mole fraction of solute  =\frac{0.64}{5.04}=0.127

\frac{122.7-p_s}{122.7}=1\times 0.127

p_s=107.12torr

Thus the vapor pressure of methanol solution at 298K is 107.12 torr

3 0
3 years ago
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