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3 years ago

Question 10

1 answer:

5 0

The reaction that should be followed is
Na2SO4 + Ca(NO3)2 --> CaSO4 + 2NaNO3
first calculate the limiting reactant
mol Na2SO4 = 0.075 L (1.54×10−2 mol / L) = 1.155x10-3 mol

mol Ca(NO3)2 = 0.075 L (1.22×10−2 mol / L) = 9.15x10-4 mol
so the limiting reactant is the Ca(NO3)2

so all of the Ca2+ will be precipitated, percentage unprecipitated = 0.00 %

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Initial alcohol is converted to compound A. Compound A undergoes three different transformations. Name compound A and each the f

nikklg [1K]

<h2>Acetic Acid</h2>

Explanation:

Initial alcohol that is formed from methane is methanol that can be converted to acetic acid.

Methanol in presence of $CO_2$ and hydrogen gas gets oxidized to acetic acid with the release of water.

Hence, compound A will be Acetic acid.

$CH_3OH + CO_2 +H_2$ → $CH_3COOH + H_2O$

The acetic acid formed can be transformed into -

$CH_3COOH$ → $CH_4 + CO$

The product formed is methane and carbon monoxide.

2. $CH_3COOH$ → $CH_2CHO + H_2O$

The product formed is formaldehyde and water.

3. $CH_3COOH + NaHCO_3$ → $CH_3COONa +CO_2 +H_2O$

The product formed is sodium acetate, carbon dioxide, and water.

4 0

2 years ago

Which of the following always changes when transmutation occurs?

mart [117]

Answer:

The atomic number

Explanation:

Transmutation refers to the conversion of one chemical element into another. A transmutation usually involves a change in the structure of atomic nuclei and this may be induced by a nuclear reaction.

Transmutation was first achieved in 1919 by Lord Rutherford when he successfully changed a nitrogen nucleus to an oxygen-18 isotope, producing a proton in the process.

Since transmutation often involves changing one atom into another, the atomic number or mass number of the original element always changes (to form a new element) in the process.

3 0

2 years ago

Given that sodium chloride is 39.0% sodium by mass, how many grams of sodium chloride are needed to have 100.mg of Na present? G

seraphim [82]

Answer: The mass of sodium chloride solution present is 0.256 grams.

Explanation:

We are given:

39.0 % of sodium in sodium chloride solution

This means that 39.0 grams of sodium is present in 100 grams of sodium chloride solution

Mass of sodium given = 100 mg = 0.1 g (Conversion factor: 1 g = 1000 mg)

Applying unitary method:

If 39 grams of sodium metal is present in 100 grams of sodium chloride solution

So, if 0.1 grams of sodium metal will be present in = $\frac{100}{39}\times 0.1=0.256g$ of sodium chloride solution.

Hence, the mass of sodium chloride solution present is 0.256 grams.

8 0

2 years ago

The equilibrium 2NO(g)+Cl2(g)⇌2NOCl(g) is established at 500 K. An equilibrium mixture of the three gases has partial pressures

QveST [7]

Answer:

For A: The $K_p$ for the given reaction is $4.0\times 10^1$

For B: The $K_c$ for the given reaction is 1642.

Explanation:

The given chemical reaction follows:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

For A:

The expression of $K_p$ for the above reaction follows:

$K_p=\frac{(p_{NOCl})^2}{(p_{NO})^2\times p_{Cl_2}}$

We are given:

$p_{NOCl}=0.24 atm\\p_{NO}=9.10\times 10^{-2}atm=0.0910atm\\p_{Cl_2}=0.174atm$

Putting values in above equation, we get:

$K_p=\frac{(0.24)^2}{(0.0910)^2\times 0.174}\\\\K_p=4.0\times 10^1$

Hence, the $K_p$ for the given reaction is $4.0\times 10^1$

For B:

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = $4.0\times 10^1$

$K_c$ = equilibrium constant in terms of concentration = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = 500 K

$\Delta ng$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-3=-1$

Putting values in above equation, we get:

$4.0\times 10^1=K_c\times (0.0821\times 500)^{-1}\\\\K_c=\frac{4.0\times 10^1}{(0.0821\times 500)^{-1})}=1642$

Hence, the $K_c$ for the given reaction is 1642.

7 0

2 years ago

What is the volume of 2 mol of chlorine gas at STP? 2.0 L 11.2 L 22.4 L 44.8 L

nirvana33 [79]

Answer:

44.8 L

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

At Standard temperature and pressure (STP);

P = 1 atm

T = 273K

Hence, when n = 2moles, the volume of the gas is:

Using PV = nRT

1 × V = 2 × 0.0821 × 273

V = 44.83

V = 44.8 L

7 0

2 years ago