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olga nikolaevna [1]
3 years ago
12

Reflect on your new experiences, what made you uncomfortable and what encouraged you. Did you learn anything new about yourself

on the trip? Traveling can help you improve. Think about your journey and if it helped you grow in any way.​
Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0

Answer:

keke

Explanation:

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A bowling ball is traveling at 3 m/s. It starts to roll up a ramp. How high above the ground will the ball be when it stops roll
Zepler [3.9K]

Answer:

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Explanation:

FREE FREE FREE FREEE FREEEEEEEEEEE FREEEEEEEEEEEEEEEE FREEEEEEEEEEEEEEEEEE

8 0
3 years ago
Read 2 more answers
A flea jumps straight up to a maximum height of 0.540 m . what is its initial velocity v0 as it leaves the ground?
jok3333 [9.3K]
For an uniformly accelerated motion, we can write
2ah=v_f^2-v_0^2
where a=g=-9.81 m/s^2 is the acceleration of this motion, which in this problem is the gravitational acceleration, with a negative sign because it points downward, against the direction of the motion; h=0.540 m is the distance covered by the flea, and v_0 is the initial velocity. 

At the maximum height, the velocity is zero, so v_f =0. Therefore we  can solve to find v_0:
v_0 =  \sqrt{2ah}= \sqrt{2(9.81 m/s^2)(0.540 m)}  =3.25 m/s
3 0
3 years ago
A steel piano string of mass per unit lenght 4×10-⁴kgm-¹ was struck, if the speed of the sound on the string is 300ms-¹. Calcula
attashe74 [19]

Answer:

36 N

Explanation:

Velocity of a standing wave in a stretched string is:

v = √(T/ρ),

where T is the tension and ρ is the mass per unit length.

300 m/s = √(T / 4×10⁻⁴ kg/m)

T = 36 N

3 0
3 years ago
The existence of the dwarf planet Pluto was proposed based on irregularities in Neptune's orbit. Pluto was subsequently discover
givi [52]

Answer:

Acceleration due to gravity, a=4.61\times 10^{-14}\ m/s^2

Explanation:

It is given that,

Mass of Pluto, m=1.4\times 10^{22}\ kg

Distance between Neptune and Pluto, r=4.5\times 10^{12}\ m

The force of gravity is balanced by the gravitational force between Neptune and Pluto. It is given by :

a=\dfrac{Gm}{r^2}

a=\dfrac{6.67\times 10^{-11}\times 1.4\times 10^{22}}{(4.5\times 10^{12})^2}

a=4.61\times 10^{-14}\ m/s^2

So, the acceleration due to gravity at Neptune due to Pluto is 4.61\times 10^{-14}\ m/s^2. Hence, this is the required solution.  

4 0
4 years ago
In which direction does centripetal force act on an object
Gwar [14]
In a circle or circular motion
5 0
4 years ago
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