Complete Question
How many turns are in its secondary coil, if its input voltage is 120 V and the primary coil has 210 turns.
The output from the secondary coil is 12 V
Answer:
The value is
Explanation:
From the equation we are told that
The input voltage is
The number of turns of the primary coil is
The output from the secondary is
From the transformer equation
Here is the number of turns in the secondary coil
=>
=>
=>
Answer:
a) always. b) electric field lines are defined by the path positive test charges travel.
Explanation:
By convention, field lines always follow the direction that it would take a positive test charge (small enough so it can´t disrupt the field created by a charge distribution), under the influence of an electric field, at the same point where the test charge is located.
So any positive charge, subject to an electric field influence, moves along the field line that passes through its current position, in the same way that a positive test charge would.
We could say also that the electric force on a positively charged particle is in the same direction as the electric field that produces that force (due to some charge distribution) , which is true, but it doesn´t explain why.
Answer:
424.26 m/s
Explanation:
Given that Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q
The relative speed will be calculated by using pythagorean theorem
Relative speed = sqrt(300^2 + 300^2)
Relative speed = sqrt( 180000 )
Relative speed = 424.26 m/s
Therefore, the magnitude of velocity of the air craft P relative to air craft Q is 424.26 m/s
Answer:
A. (1/T₂ - 1/T₁) = -2.69 x 10⁻⁴ K⁻¹
B. ln (k₁/k₂) = -3.434
C. E = 106.13 KJ/mol
Explanation:
Part A:
we have:
T₁ = 25°C = 298 K
T₂ = 51°C = 324 K
(1/T₂ - 1/T₁) = (1/324 k - 1/298 k)
<u>(1/T₂ - 1/T₁) = -2.69 x 10⁻⁴ K⁻¹</u>
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Part B:
ln (k₁/k₂) = ln (0.1/3.1)
<u>ln (k₁/k₂) = -3.434</u>
Part C:
The activation energy can be found out by using Arrhenius Equation:
ln (k₁/k₂) = E/R (1/T₂ - 1/T₁)
where,
E = Activation Energy
R = General Gas Constant = 8.314 J/mol.k
Therefore,
-3.434 = (E/8.314 J/mol.k)(-2.69 x 10⁻⁴ K⁻¹)
<u>E = 106134.8 J/mol = 106.13 KJ/mol</u>
Answer:
12,740 N
Explanation:
The weight of the hyppogriff is given by:
where
m = 1300 kg is the hippogriff's mass
g = 9.8 m/s^2 is the acceleration due to gravity
Substituting the numbers into the equation, we get: