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Ostrovityanka [42]
3 years ago
7

In a low-density cloud, the internal pressure is much too low to support the weight, so the cloud must __________, eventually pr

oducing the galaxy s disk.
Physics
1 answer:
andrey2020 [161]3 years ago
3 0

The answer to this question is flatten

so the cloud must <u>flatten</u> eventually producing the galaxy s disk.

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10) Um viajante, ao desembarcar no aeroporto de Londres, observou que o valor da temperatura do ambiente na escala Fahrenheit é
joja [24]

Answer:

The observed temperature was 10º Celsius or 50º Fahrenheit.

Explanation:

The traveler observed that the temperature in Fahrenheit is five times the value of the temperature in Celsius, therefore:

F = 5*C

A Fahrenheit temperature relates to a Celsius one by the following expression:

F = \frac{9}{5}*C + 32

Using the second expression on the first, we can solve for the temperature in Celsius, this is done below:

\frac{9}{5}*C + 32 = 5*C\\\frac{9}{5}*C - 5*C = -32\\\frac{9*C - 25*C}{5} = -32\\\frac{-16*C}{5} = -32\\-16*C = -32*5\\-16*C = -160\\C = \frac{-160}{-16} = 10\º\text{C}\\F = 5*C = 5*10 = 50\º\text{F}

The observed temperature was 10º Celsius or 50º Fahrenheit.

7 0
3 years ago
Which of the following will not have the same number of valence electrons?
nexus9112 [7]
Carbon is the answer to the problem
4 0
3 years ago
Having landed on a newly discovered planet, an astronaut sets up a simple pendulum of length 1.38 m and finds that it makes 441
Tasya [4]
The period of a simple pendulum is given by:
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the pendulum length, and g is the gravitational acceleration of the planet. Re-arranging the formula, we get:
g= \frac{4 \pi^2}{T^2}L (1)

We already know the length of the pendulum, L=1.38 m, however we need to find its period of oscillation.

We know it makes N=441 oscillations in t=1090 s, therefore its frequency is
f= \frac{N}{t}= \frac{441}{1090 s}=0.40 Hz
And its period is the reciprocal of its frequency:
T= \frac{1}{f}= \frac{1}{0.40 Hz}=2.47 s

So now we can use eq.(1) to find the gravitational acceleration of the planet:
g= \frac{4 \pi^2}{T^2}L =  \frac{4 \pi^2}{(2.47 s)^2} (1.38 m) =8.92 m/s^2
3 0
3 years ago
During its lifespan, what characteristics of the sun will change
4vir4ik [10]
During its lifepsan, the sun's core would keep contracting and heating up.

The temperature will keep increasing to the point where the temperature outside the core will get to hydrogen fusion temperatures.
The sun will grow in surface and eventually became the Red Giant
6 0
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