The magnitude of the electric field just outside the surface of the sphere is
given:
radius,r=0.01m
charge,Q=1.0×10-9
what is electric field?
Electric field is defined as the electric force per unit charge.It is surrounded by electrically charged particles and exerts force on all other charge particles.
using formula,
for just outside r=radius of sphere
Thus,the electric field just outside the surface of the sphere is
learn more about electric field from here: brainly.com/question/28203588
#SPJ4
Current is defined as the rate of charge flowing a point every second. Having a current of 1 Ampere signifies 1 Coulomb is flowing in a circuit every second. It is measured by the use of an ammeter which is positioned in series to the component to be measured. The current in the problem is calculated as follows:
I = 2.0 x 10^-4 C / 5.0 x 10^-5 s
<span>I = 4 A</span>
<span>C) 28 km
Magnitude = </span>√(20² + 20²)
= 26.28km
Since the temperature of the gas remains constant in the process, we can use Boyle's law, which states that for a gas transformation at constant temperature, the product between the gas pressure and its volume is constant:
which can also be rewritten as
(1)
where the labels 1 and 2 mark the initial and final conditions of the gas.
In our problem,
,
and
, so the final pressure of the gas can be found by re-arranging eq.(1):
Therefore the correct answer is
<span>1. 0.75 atm</span>