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Anni [7]
2 years ago
13

Which option is an example of a physical property?

Physics
1 answer:
Lera25 [3.4K]2 years ago
5 0

Answer:

it may be that last one

Explanation:

lol i may be incorrect:)

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A typical loaded commercial jet airplane has an inertia of 2.1 × 105 kg (a) Which do you expect to require more energy: getting
MrMuchimi

Answer:

(a) It depends on what cruising speed and cruising altitude

(b) 7654.5 * 10^6 (J)

(c) 21425.04 * 10^6 (J)

Explanation:

Formula for Kinetic energy: E_k = \frac{mv^2}{2}

Formula for Potential energy E_p = mgh

(a) It actually depends on cruising speed and cruising altitude to tell which one requires more energy. However, cruising speed would have more impact than cruising altitude because it has a power of 2 in the energy formula.

(b) If we plug in v = 270 and m = 210000 to the Kinetic energy formula we should have

E_k = \frac{210000 * 270^2}{2} = 7654.5 * 10^6 (J)

(c) If we plug in h = 10.4 km = 10400 m, m = 210000 and g = 9.81 we should have

E_p = 210000 * 9.81 * 10400 = 21425.04 * 10^6 (J)

6 0
3 years ago
Kepler’s third law states that for all objects orbiting a given body, the cube of the semimajor axis (A) is proportional to the
GarryVolchara [31]

Explanation:

Kepler’s third law states that for all objects orbiting a given body, the cube of the semimajor axis (A) is proportional to the square of the orbital period (P).

For each of our planets orbiting the Sun, the relationship between the orbital period and semimajor axis can be represented by the equation as:

P^2=kA^3

k is constant of proportionality

It is required to solve the above equation for k

k=\dfrac{P^2}{A^3}

8 0
3 years ago
Does the sun fuse hydrogen into helium or vice versa?
NikAS [45]

Hydrogen has the smaller, lighter, simpler nucleus.
Helium has the larger, heavier, more complex nucleus.
Hydrogen nuclei are fused to form helium nuclei. 
When that happens, energy is released. 

6 0
2 years ago
Kuiper Belt objects are composed of which substances? Select all that apply.
levacccp [35]
IM sure there is C, D, and E in kuiper belts, but not really sure of silicon and iron

8 0
3 years ago
(15 Points)
oksian1 [2.3K]

The vertical weight carried by the builder at the rear end is F = 308.1 N

<h3>Calculations and Parameters</h3>

Given that:

The weight is carried up along the plane in rotational equilibrium condition

The torque equilibrium condition can be used to solve

We can note that the torque due to the force of the rear person about the position of the front person = Torque due to the weight of the block about the position of the front person

This would lead to:

F(W*cosθ) = mgsinθ(L/2) + mgcosθ(W/2)

F(1cos20)= 197/2(3.10sin20 + 2 cos 20)

Fcos20= 289.55

F= 308.1N

Read more about vertical weight here:

brainly.com/question/15244771

#SPJ1

5 0
2 years ago
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