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yaroslaw [1]
4 years ago
11

PLEASE HELP!!!

Physics
1 answer:
Brilliant_brown [7]4 years ago
8 0

Answer:23 seconds

Explanation:

Acceleration(a)=3.87m/s^2

distance(d)=1020m

Initial velocity(u)=0

d=uxt + (axt^2)/2

1020=0xt + (3.87xt^2)/2

1020=(3.87xt^2)/2

Cross multiply

1020x2=3.87xt^2

2040=3.87xt^2

t^2=2040/3.87

t^2=527.13

t=22.95

Time(t) is approximately 23seconds

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