Answer:
K.E = 25 J
Explanation:
Given data:
Mass of ball = 0.5 g
Velocity of ball = 10 m/s
Kinetic energy = ?
Solution:
Formula:
K.E = 1/2 mv²
m = mass
v = velocity
Now we will put the values in formula.
K.E = 1/2 mv²
K.E = 1/2× 0.5kg × (10m/s)²
K.E = 1/2 ×0.5kg × 100m²/s²
K.E = 25 Kg.m²/s²
Kg.m²/s² = J
K.E = 25 J
This is an example of Charles’ Law problems, the basic equation is: V1/T1 = V2/T2. One vital thing to recall for all gas law problems is that the temperature must be in Kelvin (not Celsius).
So our given is 10.0 C = 283 K. So
V1/T1 = V2/T2
733/283 = 950/T2
T2 = 367 K
A. Air expands, becomes less dense and rises when the temperature is high due to the increased kinetic energy. This causes the air molecules to move around much more so they are further apart.
