<h3>
Answer:</h3>
8 alpha particles
4 beta particles
<h3>
Explanation:</h3>
<u>We are given;</u>
- Neptunium-237
- Thallium-205
- Neptunium-237 undergoes beta and alpha decay to form Thallium-205.
We are required to determine the number of beta and alpha particles produced to complete the decay series.
- We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
- When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.
In this case;
Neptunium-237 has an atomic number 93, while,
Thallium-205 has an atomic number 81.
Therefore;
²³⁷₉₃Np → x⁴₂He + y⁰₋₁e + ²⁰⁵₈₁Ti
We can get x and y
237 = 4x + y(0) + 205
237-205 = 4x
4x = 32
x = 8
On the other hand;
93 = 2x + (-y) + 81
but x = 8
93 = 16 -y + 81
y = 4
Therefore, the complete decay equation is;
²³⁷₉₃Np → 8⁴₂He + 4⁰₋₁e + ²⁰⁵₈₁Ti
Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.
Answer:The masses of the reactants and products formed are not included in the question, so we cannot determine the percentage yield of water without knowing the yields of other substances.
However the formulae for percentage yield is;
Percentage yield=experimental yield/theoretical yield X 100
Answer: technetium-99.
Explanation:
This is not an answer that you can look for in a book.
You need to do some research.
You can fiind the abstract of the article titled <span>Molecular imaging of atherosclerosis using a technetium-99m-labeled endothelin derivative.</span>
The conclusion of this scientific article is that labeling with the radiosotope Tc - 99 iis feasibele to visualize the effects of an experiment inducing atherosclerosis, which gives the answer to the question posted.
.
The electron configuration that represents the nitride ion<span> is 1s² 2s²2p⁶</span>
