Atomic mass of magnesium = (23.99 x 78.99%) + (24.99 x 10.00%) + (25.98 x 11.01%)
= 24.31 g/mol
Answer:
Molar Mass of Calcium Carbonate = 100g
given mass = 50g
Number of mole of Calcium Carbonate =50/100 = 0.5 mole
Molarity = mole per litre of volume
Molarity = 0.5 /0.25 = 2mole/litre
Explanation:
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Answer:
Average atomic mass = 63.553 amu.
Explanation:
Given data:
Abundance of Y-63 = 69.17%
Abundance of Y-65 = 100 - 69.17 = 30.83%
Atomic mass of Y-63 = 62.940 amu
Atomic mass of Y-65 = 64.928 amu
Atomic mass of Y = ?
Solution:
Average atomic mass= (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass= (62.940×69.17)+(64.928×30.83) /100
Average atomic mass = 4353.560 + 2001.730 / 100
Average atomic mass = 6355.29 / 100
Average atomic mass = 63.553 amu.
Answer:
25 coolers are need to be produce and sell in order to minimize the cost.
Explanation:
..[1]
Differentiating the given expression with respect to dx.
Putting ,
x = 25
Taking second derivative of expression [1]
(minima)
25 coolers are need to be produce and sell in order to minimize the cost.
