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oksano4ka [1.4K]
3 years ago
12

EXPLAIN How would you explain the difference between single displacement and

Chemistry
1 answer:
IrinaK [193]3 years ago
3 0
  • The difference between single displacement reaction and double displacement reaction are:

Explanation:

in the chemical reaction an atom in a molecule is replaced by another atom forming the end product .this type of chemical reaction involved only two reactants for example zinc + copper sulphate give us copper sulphate + copper.double displacement reaction is the reaction in which two compounds react together to form two other compounds by mutual exchange of other ions is called double displacement reaction.this type of reaction is involved two or more than two reactants.for example AG and O3 + NaCl give us agcl + nano3

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Given that Delta.G for the reaction below is –957.9 kJ, what is Delta.Gf of H2O?
Alexxandr [17]

Answer:

6ΔG°(f) H₂O = -229 Kj/mol

Explanation:

                    4NH₃(g)          +      5O₂(g)       =>        4NO(g)           +     6H₂O(g)

ΔG°(f) 4mol(-16.66Kj/mol) | 5mol(0Kj/mol) || 4mol(+86.71Kj/mol) | 6ΔG°(f) H₂O

Hess's Law

ΔG°(Rxn) = ∑ΔG°(f) Products - ∑ΔG°(f) Reactants

-957.9 Kj = [(4mol(+86.71Kj/mol)) + 6ΔG°(f) H₂O(g)] - [4mol(-16.66Kj/mol) + 5mol(0Kj/mol)]

-957.9 Kj = [4(86.7)Kj + 6ΔG°(f) H₂O] - [4(-16.66)Kj] = 346.84Kj + 6ΔG°(f) H₂O + 66.64Kj

ΔG°(f) H₂O = ((-957.9 - 346.84 -66.64)/6)Kj =  -228.56 Kj ≅ -228.6 Kj*

*Verified with Standard Heat of Formation Table

8 0
3 years ago
Sort the metric system prefixes into the correct order, smallest to largest.
AleksAgata [21]

Answer:

mili

hecto

deci

deca

centi

kilo

Explanation:

7 0
3 years ago
Read 2 more answers
Copper has two naturally occurring isotopes, 63Cu (isotopic mass 62.9296 amu) and 65Cu (isotopic mass 64.9278 amu). If copper ha
Semenov [28]

Answer:

Percentage of first isotope = 69.152 %

Percentage of second isotope =  30.848 %

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

For first isotope:

Let % = x %

Mass = 62.9296 amu

For second isotope:

% = 100 - x  %  (Since, there are only two isotopes)

Mass = 64.9278 amu

Average mass = 63.546 amu

Thus,  

63.546=\frac {x}{100}\times {62.9296}+\frac {(100-x)}{100}\times {64.9278}

Solving,

1.9982 x = 138.18

Thus,

<u>Percentage of first isotope = x = 69.152 %</u>

<u>Percentage of second isotope = 100 - x % = 30.848 %</u>

5 0
4 years ago
The nitrogen oxide (NO) molecule has a bond length of 140 pm. Calculate the dipole moment, in Debyes, that results if the charge
Cloud [144]

Answer:

Explanation:

Dipole moment = charge x separation of charges

= (2 x 1.6 x 10⁻¹⁹ ) x ( 140 x 10⁻¹² ) coulomb-metre

= 448 x 10⁻³¹coulomb-metre

1 debye = 3.33 x 10⁻³⁰coulomb-metre

Dipole moment in debye =  448 x10⁻³¹ / 3.33 x 10⁻³⁰debye

= 448 x10⁻³¹ / 33.3 x 10⁻³¹

= 13.45 debye

=

6 0
3 years ago
What are the mole fraction and the mass percent of a solution made by dissolving 0.21 g KBr in 0.355 L water? (d = 1.00 g/mL.) m
IRISSAK [1]

Answer:

Mol fraction H2O = 0.99991

Mol fraction KBr = 0.00009

mass % KBr = 0.059 %

mass % H2O = 99.941 %

Explanation:

Step 1: Data given

Mass of KBr = 0.21 grams

Molar mass KBr = 119 g/mol

Volume of water = 355 mL

Density of water = 1.00 g/mL

Molar mass water = 18.02 g/mol

Step 2: Calculate mass water

Mass water = 355 mL * 1g /mL

Mass water = 355 grams

Step 3: Calculate moles water

Moles water = mass water / molar mass water

Moles water = 355 grams / 18.02 g/mol

Moles water = 19.7 moles

Step 4: Calculate moles KBr

Moles KBr = 0.21 grams / 119 g/mol

Moles KBr = 0.00176 moles

Step 5: Calculate total moles

Total moles = 19.7 moles + 0.00176 moles

Total moles = 19.70176 moles

Step 6: Calculate mol fraction

Mol fraction H2O = 19.7 moles / 19.70176 moles

Mol fraction H2O = 0.99991

Step 7: Calculate mol fraction KBr

Mol fraction KBr = 0.00176 / 19.70176

Mol fraction KBr = 0.00009

Step 6: Calculate mass %

mass % KBR = (0.21 grams / (0.21 + 355) grams) *100%

mass % KBr = 0.059 %

mass % H2O = (355 grams / 355.21 grams) *100%

mass % H2O = 99.941 %

8 0
3 years ago
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