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IRISSAK [1]
3 years ago
13

What is a real world example of reflection

Chemistry
1 answer:
trapecia [35]3 years ago
5 0

Answer:

Real life examples of reflections are: the symmetry of your face, a butterfly, an airplane and so many more objects. mass production of shoes and spectacle frames. flipping images on a computer. the mirror images of the chemical structure of the sugar molecules, glucose (in sugarcane) and fructose (in fruit).

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Explain the term 'end point'?<br> What do you mean by a 1.0 M solution?
andrey2020 [161]

Answer:

According to me end point is the end of a reaction

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2 years ago
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How many molecules are in
diamong [38]

Answer:

3.6 × 10²⁴ molecules

Explanation:

Step 1: Given data

Moles of methane (n): 6.0 moles

Step 2: Calculate the number of molecules of methane in 6.0 moles of methane

In order to convert moles to molecules, we need a conversion factor. In this case, we will use Avogadro's number: there are 6.02 × 10²³ molecules of methane in 1 mole of molecules of methane.

6.0 mol × 6.02 × 10²³ molecules/1 mol = 3.6 × 10²⁴ molecules

6 0
2 years ago
What is the difference between energy levels, sub levels, and orbitals?
Lorico [155]

Explanation:

Orbitals are spaces that have a high probability of containing an electron. ... The s sublevel has just one orbital, so can contain 2 electrons max. The p sublevel has 3 orbitals, so can contain 6 electrons max. The d sublevel has 5 orbitals, so can contain 10 electrons max.

7 0
3 years ago
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1
zzz [600]

Answer:

i think kinetic energy sorry if I'm wrong.

6 0
3 years ago
3. A student measured 15.0 grams of ice in a beaker. The beaker was then
gregori [183]

Answer:

The heat that was used to melt the 15.0 grams of ice at 0°C is 4,950 Joules

Explanation:

The mass of ice in the beaker = 15.0 grams

The initial temperature of the ice = 0°C

The final temperature of the ice = 0°C

The latent heat of fusion of ice = 330 J/g

The heat required to melt a given mass of ice = The mass of the ice to be melted × The latent heat of fusion of ice

Therefore, the heat, Q, required to melt 15.0 g of ice = 15.0 g × 330 J/g = 4,950 J

The heat that was used to melt the 15.0 grams of ice = 4,950 Joules.

3 0
3 years ago
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