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matrenka [14]
3 years ago
10

Determine if the two triangles are congruent. If they are State how you know. NO LINKS!!!​

Mathematics
1 answer:
miv72 [106K]3 years ago
3 0

Problem 25

These triangles are congruent.

The reasoning is the AAS congruence theorem. We have two pairs of congruent angles, as shown by the arc markings, and a pair of congruent sides. The sides are <u>not</u> between the angles. That means AAS is slightly different from ASA. The order matters.

=====================================================

Problem 26

The triangles are <u>not</u> congruent

Why not? Well it all comes down to the angle placement. For the triangle on the right side, the arc is between the shared segment and the segment with the double tickmarks. The other arc is not in the proper corresponding location to be able to use SAS. It would need to be adjacent to the arc on the right for us to use SAS.

If it's hard to visualize what I mean, refer to the diagram below.

=====================================================

Problem 27

The triangles are <u>congruent</u> by <u>SAS</u>

The angles aren't marked, but recall that vertical angles are always congruent. So you could add in angle markers if you wanted, to help complete the diagram. The tickmarks of course tell us which segments are the same length. The angles are between the segments.

====================================================

Problem 28

The triangles are <u>congruent</u> by <u>SSS</u>

Like before, the tickmarks tell us which sides are the same length. So the tickmarks say that we have two pairs of congruent sides. The overlapping sides or shared sides are the third pair of congruent segments. So in reality, we have three pairs of congruent sides. It might help to break up the figure into two separate triangles.

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Troyanec [42]

9514 1404 393

Answer:

   arc AB = 12.4 cm

Step-by-step explanation:

The length of arc AB is 1/4 of the circumference of the circle, so is ...

  AB = (1/4)(2πr)

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Rounded to the nearest tenth, arc AB = 12.4 cm.

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alexandr402 [8]
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AleksandrR [38]

Seven huge boxes and two tiny boxes total were bought by the contractor.

A linear equation is defined as an algebraic equation of maximum degree 1 is a linear equation.

According to the question, a builder needs to purchase nails to construct a house.

Both small and large boxes of nails are provided. There are 50 nails in each small box and 350 in each large box.

The contractor purchased 5 more large than tiny boxes, hence it is assumed that he purchased a certain number of little boxes.

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400x = 2590 - 1750.

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The bulk of the boxes he bought is 7.

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nexus9112 [7]
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Answer:

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