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guapka [62]
3 years ago
8

Anybody woke im ???????????????????

Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0

Answer:

whatrtsusbssjndkdkdjdj

Marina86 [1]3 years ago
6 0
Yuhhhhhhhh whatever that means
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What is 4 1/2 (-2+1+7) =
NeTakaya

Answer:

27

Step-by-step explanation:

convert calculate 9\2×6

reduce the numbers 9×3 =27

4 0
3 years ago
The domaln of the following relation R ((6, -2), (1, 2), (-3, -4), (-3, 2)} Is (1 polnt)
castortr0y [4]

Answer:

A. -3,-3,1,6

Step-by-step explanation:

The domain of a relation is the x-coordinates.

7 0
3 years ago
What is y=4/5x+4 in standard form
HACTEHA [7]
5y = 4x + 20
- 4x + 5y = 20
5 0
2 years ago
P (6,6) y=2/3x
matrenka [14]

Answer:

y = -\frac{3}{2}x+15

Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

y = \frac{2}{3}x

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

y = \frac{2}{3}x

Now, we compare the given equation by standard form y = mx +c

So, slope of the line m_{1} = \frac{2}{3}, and

y-intercept c=0

We know that the slope of the perpendicular line m_{1}\times m_{2}  = -1

m_{2}=-\frac{1}{m_{1}}

m_{2}=-\frac{1}{\frac{2}{3} }

m_{2}=-\frac{3}{2}

So, the slope of the perpendicular line m_{2}=-\frac{3}{2}

From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

y=mx+c

Substitute point P(x_{1}, y_{1})=P(6, 6) and m = m_{2}=-\frac{3}{2}

6=-\frac{3}{2}\times 6 +c

6=-3\times 3 +c

c=6+9

c=15

So, the y-intercept of the perpendicular line c=15

Using point slope formula.

y=mx+c

Substitute m = m_{2}=-\frac{3}{2} and c=15 in above equation.

y = -\frac{3}{2}x+15

Therefore: the equation of the perpendicular line y = -\frac{3}{2}x+15

8 0
3 years ago
Find a polynomial with a degree of 3 and zeros -3,3,5
Aliun [14]

Answer:

f(x) = x³ - 5x² - 9x + 45

Step-by-step explanation:

Given x = a, x = b are the zeros of a polynomial, then

(x - a), (x - b) are the factors and f(x) is the product of the factors.

Here the zeros are x = - 3, x = 3 and x = 5, thus

(x + 3), (x - 3) and (x - 5) are the factors and

f(x) = (x + 3)(x - 3)(x - 5) ← expand the first pair of factors using FOIL

     = (x² - 9)(x - 5) ← distribute

    = x³ - 5x² - 9x + 45

   

6 0
3 years ago
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