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3 years ago

15

What is the DMS measure of an angle that is 3.7 radians?

1 answer:

Nostrana [21]3 years ago

7 0

C. Because it equals to the degrees to the 3.7 radians

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Give the difference of 8/13 and 5/13<br><br> A. 3/13<br> B. 8/13<br> C. 5/13

nikitadnepr [17]

Answer:

3/13

Step-by-step explanation:

8/13 subtract by 5/13. If the denominator is the same, you keep it, don't change it. Just subtract the numerator.

Make sure to simplify, if it is already simplified that will be the answer.

5 0

1 year ago

Read 2 more answers

(b) In the figure below, m 2AEB= 55° and m AB = 60°. Find m CD.<br><br> m CD =

RUDIKE [14]

Answer:

47 degrees

Explanation:

your welcome

4 0

2 years ago

What does x equal in 3(x-2)=-3

Maru [420]

Answer:

Step-by-step explanation:

3(x-2)= -3

Divide both sides by 3

x-2 = -1

add 2 to both sides

x - 2 +2 = -1 + 2

x = 1

6 0

2 years ago

Read 2 more answers

I am about to get my homework done I just need these two. (Thank you if you answer!!)

AnnZ [28]

Answer:

$-7=h\\-6.81=q$

Step-by-step explanation:

For question #1:

$-3=h+8/2\\-3=h+4\\-7=h$

For question #2:

$q+16.41=9.6\\q=-6.81$

8 0

1 year ago

System of Equations <br> Need help<br> Trig

Yanka [14]

Looks like the system is

$\begin{cases}-2x+y+6z=1\\3x+2y+5z=16\\7x+3y-4z=11\end{cases}$

We can eliminate $y$ by taking

$(3x+2y+5z)-2(-2x+y+6z)=16-2(1)$

$\implies3x+2y+5z+4x-2y-12z=16-2$

$\implies7x-7z=14$

$\implies x-z=2$

so that $z=x-2$ , and

$(7x+3y-4z)-3(-2x+y+6z)=11-3(1)$

$\implies7x+3y-4z+6x-3y-18z=11-3$

$\implies13x-22z=8$

Substitute $z=x-2$ into this last equation and solve for $x$ :

$13x-22(x-2)=8$

$\implies13x-22x+44=8$

$\implies-9x=-36$

$\implies x=4$

Then

$z=x-2$

$\implies z=4-2$

$\implies z=2$

Plug these values into any one of the original equation to solve for $y$ :

$-2x+y+6z=1$

$\implies-2(4)+y+6(2)=1$

$\implies-8+y+12=1$

$\implies y=-3$

Hence the solution is x = 4, y = -3, and z = 2.

6 0

3 years ago