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Mariana [72]
3 years ago
14

if i initially have 4.0 L of a gas at a pressure of 1.1 atm, what will the volume be if i increase the pressure to 3.4 atm

Chemistry
1 answer:
Lelechka [254]3 years ago
6 0

Answer:

<h3>The answer is 1.29 L</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{4 \times 1.1}{3.4}  =  \frac{4.4}{3.4} \\   =1.294117647...

We have the final answer as

<h3>1.29 L</h3>

Hope this helps and

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3 years ago
A gas sample has a temperature of 19 °C with an unknown volume. The
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Answer: 373 mL

Explanation:

Since there is no change in pressure, the formula: V / T = V / T can be used.

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2 years ago
Why is it important for scientists to review and repeat the work of other scientists
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Answer:

Accuracy

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2 years ago
At a given temperature the vapor pressure of pure liquid benzene and toluene are 745 torr and 290 torr, respectively. A solution
IRISSAK [1]

Answer:

Vapour pressure of benzene over the solution is 253 torr

Explanation:

According to Raoult's law for a mixture of two liquid component A and B-

vapour pressure of a component (A) in solution = x_{A}\times P_{A}^{0}

vapour pressure of a component (B) in solution = x_{B}\times P_{B}^{0}

Where x_{A},x_{B} are mole fraction of component A and B in solution respectively

P_{A}^{0},P_{B}^{0} are vapour pressure of pure A and pure B respectively

Here mole fraction of benzene in solution is 0.340 and vapour pressure of pure benzene is 745 torr

So, vapour pressure of benzene in solution = 0.340\times 745 torr

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Answer:

Hope this will help you

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3 years ago
Read 2 more answers
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