Answer:
1. The reaction will proceed backward, shifting the equilibrium position to the left.
2. The reaction will proceed forward, shifting the equilibrium position to the right.
3. Either add more of the products ( H2O or Cl2) or remove the reactant (HCl or O2)
Explanation:
Answer:
The correct answer is Pu, 234.
Explanation:
In the given case, let us consider the reactant as X. Now the mass number (balanced) on both the sides will be,
Mass of X = Mass of Molybdenum + Mass of Tin + Mass of neutrons
M = 1 * 103 + 1 * 131 + 2 * 0
M = 234
Now the atomic number (balanced) on both the sides,
Atomic number of X = Atomic number of Molybdenum + Atomic number of Tin + Atomic number of neutrons
A = 1*42 + 1*50 + 2*1
A = 94
The atomic number 94 is for the element Plutonium, whose symbol is Pu. Thus, the reactant is 234-Pu.
Answer:
NH₄⁺
H₂PO₄⁻
H₃O⁺
Explanation:
- An ion is an atom or molecule with a net electric charge due to the loss or gain of one or more electrons.
- Ion may be positively charged "cation" or negatively charged "anion".
- Neutral molecule has a net charge of zero.
<em>So, the species that are ions are: </em>
NH₄⁺
H₂PO₄⁻
H₃O⁺
Answer: 
of NaOH
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
Putting in the values:
![10.020=-\log[H^+]](https://tex.z-dn.net/?f=10.020%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=9.55\times 10^{-11}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D9.55%5Ctimes%2010%5E%7B-11%7D)
![[H^+][OH^-]=10^{-14}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%5BOH%5E-%5D%3D10%5E%7B-14%7D)
![[OH^-]=\frac{10^{-14}}{9.55\times 10^{-11}}=1.05\times 10^{-4}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%5Cfrac%7B10%5E%7B-14%7D%7D%7B9.55%5Ctimes%2010%5E%7B-11%7D%7D%3D1.05%5Ctimes%2010%5E%7B-4%7DM)
moles = 
Mass of 
Thus of NaOH is needed to prepare 463 mL of solution with a pH of 10.020
