Based on recommended amount of carbohydrate, a basketball player should consume about 17 - 34 ounces of gatorade g series during the hour-long game.
<h3>How many ounces of endurance formula gatorade g series, endurance formula should a basketball player consume during an hour-long game if it contains 14 grams of carbohydrate per 8 ounces?</h3>
Carbohydrates are food substances metabolized easily by the body to produce energy.
Given that the recommended amount of carbohydrate to consume to maintain performance is 30–60 g/h.
Also 14 grams of carbohydrate found in 8 ounces of the drink.
30 g of carbohydrate will be present in 30 × 8/14 = 17.1 ounces of gatorade g series
60 g of carbohydrate will be present in 60 × 8/14 =34.3 ounces of gatorade g series.
Therefore, a basketball player should consume about 17 - 34 ounces of gatorade g series during the hour-long game.
Learn more about carbohydrates at: brainly.com/question/797978
Answer:
5.625 moles of oxygen, O₂.
Explanation:
The balanced equation for the reaction is given below:
4Al + 3O₂ —> 2Al₂O₃
From the balanced equation above,
4 moles of Al reacted with 3 moles of O₂.
Finally, we shall determine the number of mole of O₂ required to react with 7.5 moles of aluminum, Al. This can be obtained as illustrated below:
From the balanced equation above,
4 moles of Al reacted with 3 moles of O₂.
Therefore, 7.5 moles of Al will react with = (7.5 × 3)/4 = 5.625 moles of O₂.
Thus, 5.625 moles of O₂ is needed for the reaction.
Even though Hydrogen is originally in group 1, based on this property, we can say it is in group 6.
Because:
Group 6 would mean that it only needs 2 more valence electrons till the octet (8 valence electrons). This would make it reactive, yet, in normal conditions, unlike group 7.
Answer:
Option B, HCO3 1-
Explanation:
The valence of Sodium ion is +1 and the valence of HCO3 is -1. Thus, sodium ion has an extra electron to be donated to complete its outer shell while HCO3 needs an electron to complete its outer shell
Hence Na will combine with HCO3 to form NaHCO3
Option B is correct
