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DENIUS [597]
3 years ago
9

What does heat, enthalpy, entropy and free energy all have in common

Chemistry
1 answer:
vekshin13 years ago
4 0

Answer: Free energy combined enthalpy and entropy into a single value. Gibbs’s free energy is the energy associated with a chemical reaction that can do useful work. It equals the enthalpy minus the product of temperature and entropy of the system.

Explanation:

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Carbon, C, P Block, 2, 6, 12.0107u. 6 protons, 6 electrons, 6 neutrons

Helium, He, S Block, 1, 2, 4.0026u, 2 protons, 2 electrons, 2 neutrons

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Oxygen, O, P Block, 2, 8, 16u, 8 protons, 8 electrons, 8 neutrons

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Tellurium, Te, P Block, 5, 52, 127.60u, 52 protons, 52 electrons, 76 neutrons

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Iron, Fe, D Block, 4, 26, 55.845u, 26 protons, 26 electrons, 30 neutrons

Beryllium, Be, S Block, 2, 4, 9.012u, 4 protons, 4 electrons, 5 neutrons

Vanadium, V, D Block, 4, 23, 50.942u, 23 protons, 23 electrons, 28 neutrons

Silver, Ag, D Block, 5, 47, 108u, 47 protons, 47 electrons, 61 neutrons

Gallium, Ga, P Block, 4, 31, 69.723u, 31 protons, 31 electrons, 39 neutrons

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What is the percent yield of a reaction in which 47.5 g tungsten (VI) oxide (WO3) reacts with excess hydrogen gas to produce met
Katarina [22]

Answer:

The percent yield of a reaction is 85.04%

Explanation:

:WO_3+3H_2\rightarrow W+3H_2O

Mass of WO_3 = 47.5g

Molar mass of WO_3 = 232 g/mole

Molar mass of H_2O= 18 g/mole

Volume of water obtained from the reaction , V= 9.40mL

Mass of water = m = Experimental yield of water

Density of water = d = 1.00 g/mL

M=d\times V = 1.00 g/mL\times 9.40 mL=9.40 g

Moles of tungsten(VI) oxide =\frac{47.5 g}{232 g/mol}=0.2047 mol

According to recation 1 mole of tungsten(VI) oxide gives 3 moles of water, then 0.2047 moles of tungsten(VI) oxide will give:

\frac{3}{1}\times 0.2047 mol=0.6141 mol

Mass of 0.6141 moles of water:

0.6141 mol × 18 g/mol = 11.054 g

To calculate the percentage yield of reaction , we use the equation:

% yield = {\frac{Experimental yield}{theoretical yield} \times 100

\frac{9.40}{11.054} \times 100\\\\= 85.04

The percent yield of a reaction is 85.04%

7 0
3 years ago
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