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vaieri [72.5K]
3 years ago
14

Calculate how many grams of sodium hypochlorite can be theoretically formed when 1.23 mol of sodium hydroxide is combined with 1

.36 mol of chlorine.
Chemistry
1 answer:
elixir [45]3 years ago
8 0

Answer:

45.78 g NaClO

Explanation:

The reaction that takes place is:

  • 2NaOH + Cl₂ → NaCl + NaClO + H₂O

In order to react completely, 1.36 moles of chlorine would require (2*1.36) 2.72 moles of NaOH. There are more moles than that, so NaOH is the limiting reactant.

We <u>calculate the moles of NaClO formed</u>, from the limiting reactant:

  • 1.23 mol NaOH * \frac{1molNaClO}{2molNaOH} = 0.615 mol NaClO

Finally we <u>convert NaClO moles to grams</u>, using its <em>molecular weight</em>:

  • 0.615 mol NaClO * 74.44 g/mol = 45.78 g NaClO
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