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3 years ago

The object will have a minimum gravitational potential energy at point A)A B)B C)C D)D

Chemistry

2 answers:

Schach [20]3 years ago

3 0

Answer: Decrease

Explanation: The downward slope causes the momentum to decrease in speed rather than increase from an higher point.

kirill [66]3 years ago

3 0

Answer:

The object will have minimum gravitational potetial energy at point B.

Explanation:

This is because the kinetic energy of the object is at its highest at point B, so the gravitational potential energy is at its lowest.

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Samples of this drawing medium have been dated back to 30,000 BCE. Group of answer choices silverpoint charcoal pencil color pen

GuDViN [60]

Charcoal is the sample of this drawing medium have been dated back to 30,000 BCE and is denoted as option B.

<h3>What is Charcoal?</h3>

This is referred to a black carbon residue which is heated in insufficient oxygen to give it a light weight.

It is used for drawing and has been in existence for as long as 30,000 BCE hence the reason why it is the most appropriate choice.

Read more about Charcoal here brainly.com/question/22220547

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7 0

2 years ago

Acetic acid (CH3COOH) is formed from its elements by the following reaction equation:

Alecsey [184]

Answer:

111 L

Explanation:

Calculation of moles of hydrogen gas:-

Mass of $H_2$ = 18.6 g

Molar mass of $H_2$ = 2.01588 g/mol

$Moles=\frac{Mass}{Molar\ mass}=\frac{18.6}{2.01588}\ mol=9.23\ mol$

According to the given reaction:-

$2C+2H_2+O_2\rightarrow CH_3COOH$

2 moles of hydrogen gas on reaction produces one mole of acetic acid gas.

So,

1 mole of hydrogen gas on reaction produces $\frac{1}{2}$ mole of acetic acid gas.

Also,

9.23 mole of hydrogen gas on reaction produces $\frac{1}{2}\times 9.23$ mole of acetic acid gas.

Moles of acetic acid gas = 4.615 moles

Given that:

Temperature = 35 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (35 + 273.15) K = 308.15 K

n = 4.615 moles

P = 1.05 atm

V = ?

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L atm/ K mol

Applying the equation as:

1.05 atm × V = 4.615 moles ×0.0821 L atm/ K mol × 308.15 K

3 0

4 years ago

A person's heartbeat is 89 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does th

andrezito [222]

I think the answer is 82.5

5 0

3 years ago

D=ut+5 make u the subject

Levart [38]

Explanation:

d=ut+5

d-5=ut

d-5/t=u

!!!!!!!

6 0

3 years ago

If 5 grams of co and 5 grams of o2 are combined according to the reaction 2co o2 --> 2co2, which is the limiting reagent?

IrinaK [193]

When 5 grams of CO and 5grams of O₂ is combined according to the reaction 2CO + O₂ ----------> 2CO₂ then Limiting reagent is CO.

Limiting reagent is the reactant that get used up in the reaction first.

According to the given reaction:

2CO + O₂ ----------> 2CO₂

5g 5g

∴ Molar mass of CO = Molar mass of C + Molar mass of O

⇒ Molar mass of CO = 14 + 16

⇒ Molar mass of CO = 28g

∴ Molar mass of O₂ = 16(2) = 32g

∴ Molar mass of CO₂ = Molar mass of C + 2(Molar mass of O)

⇒ Molar mass of CO₂ = 14 + 2(16)

⇒Molar mass of CO₂ =44g

Let's find out the moles of CO and O₂

∴ Moles = Given mass / Molar mass

⇒ moles of CO = 5/28 = 0.17

⇒ moles of O₂ = 5/32 = 0.15

For finding out the Limiting Reagent, we will divide the number of moles with the stiochiometry of the given reaction.

⇒ For CO = Moles/ stiochiometry = 0.17/2 = 0.085

⇒ For O₂ = Moles/ stiochiometry = 0.15/1 = 0.15

Since, the ratio of number of moles with the stiochiometry is less for CO hence it is the Limiting reagent, i.e. it will get used up in the reaction first.

Hence, the Limiting reagent for the reaction is CO.

Learn more about Limiting reagent here, brainly.com/question/11848702

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8 0

1 year ago