Answer:n = PV/RT = 0.923 atm x 0.250 L / (0.082057 x 290.75 K) . n = 0.00967. mole 0.00967 mole x 6.22x10^23 molecules/mole = 6.02x10^21 molecules of gas

Explanation:

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3 years ago

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The freezing temperatures for water for Celsius and Fahrenheit scales are 0ºC and 32ºF. The boiling temperatures for water are 1

ddd [48]

Answer:

Therefore the required function is

$C= \frac{5}{9} (F-32)$

Therefore 25°C=57°F

Explanation:

F denotes temperature of Fahrenheit and C denotes temperature of Celsius.

$\frac{C-0}{100-0} =\frac{F-32}{212-32}$

$\Rightarrow C= \frac{100}{180} (F-32)$

$\Rightarrow C= \frac{5}{9} (F-32)$

Therefore the required function is

$C= \frac{5}{9} (F-32)$

Putting C=25°C in above equation

$25=\frac{5}{9} (F-32)$

$\Rightarrow 25 \times \frac{9}{5} = F-32$

⇒45 =F-32

⇒F=32+45

⇒F=57

Therefore 25°C=57°F

7 0

3 years ago